I am using a table with alternate row color with this.
tr.d0 td { background-color: #CC9999; color: black; } tr.d1 td { background-color: #9999CC; color: black; }
<table> <tr class="d0"> <td>One</td> <td>one</td> </tr> <tr class="d1"> <td>Two</td> <td>two</td> </tr> </table>
Here I am using class for tr
, but I want to use only for table
. When I use class for table than this apply on tr
alternative.
Can I write my HTML like this using CSS?
<table class="alternate_color"> <tr><td>One</td><td>one</td></tr> <tr><td>Two</td><td>two</td></tr> </table>
How can I make the rows have "zebra stripes" using CSS?
You can use this css to select every other paragraph by changing the css to "p:nth-child(even)", or list items: li:nth-child(even), etc. Change "even" to "odd" if you want the shading to affect odd rows.
$(document).ready(function() { $("tr:odd").css({ "background-color":"#000", "color":"#fff"}); });
tbody td{ padding: 30px; } tbody tr:nth-child(odd){ background-color: #4C8BF5; color: #fff; }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <table border="1"> <tbody> <tr> <td>1</td> <td>2</td> <td>3</td> <td>4</td> </tr> <tr> <td>5</td> <td>6</td> <td>7</td> <td>8</td> </tr> <tr> <td>9</td> <td>10</td> <td>11</td> <td>13</td> </tr> </tbody> </table>
There is a CSS selector, really a pseudo-selector, called nth-child. In pure CSS you can do the following:
tr:nth-child(even) background-color: #000000; }
Note: No support in IE 8.
Or, if you have jQuery:
$(document).ready(function() { $("tr:even").css("background-color", "#000000"); });
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