I wrote a function to squire number and try to cover all the input possibilities.
Overall it works fine with numeric input, but it starts a infinite loop of printing statements on screen when I enter alphabetical input.As all we know that inside computer single character like "A or a or b or B" so on is represented by integers and as i learned from my teacher that we can store single characters into a variable with integer data type. i am not talking about strings which means collection of characters . this program create problem with single character !
#include <iostream>
#include <string>
using namespace std;
void squire();
int main() {
squire();
}
void squire() {
double num = 1.0, pow = 1.0, Squire_Number = 1.0;
char ans;
reStart:
cout << "please Enter the Number: \n";
cin >> num;
cout << "please enter the nmber you want to power the number with: \n";
cin >> pow;
if (num > 0 && pow>0) {
for (int i = 1; i <= pow; i++) {
Squire_Number *= num;
}
cout << pow << " power of " << num << " is equil to : " << Squire_Number;
goto option;
}
else
{
cout << "Please enter Positve Integers. \n" ;
option:
cout<< "\nPease type 'Y' to Enter the values again OR type 'c' to Exit ! \n";
cin >> ans;
if (ans == 'y' || ans == 'Y') {
goto reStart;
} else if (ans == 'c' || ans == 'C') {
cout << "thank you for using our function. \n";
}
}
return;
}
Better try to read the input in an std::string, then parse the string to check if you only have numeric characters and then use std::atoi to convert the string in integer. One last recomendation, avoid to use goto instructions, this practice make a code difficult to read.
#include <iostream>
#include <string>
#include <cstdlib>
bool OnlyNumeric(const std::string& numStr)
{
size_t len= numStr.length();
int i;
for (i=0;i<len && numStr[i] <='9' && numStr[i] >='0';i++) ;
return i == len;
}
int main()
{
std::string inputStr;
int num;
do{
std::cout << "Input number:\n";
std::cin >> inputStr;
}
while (!(OnlyNumeric(inputStr) && (num=std::atoi(inputStr.c_str())) ));
std::cout << "Your number is : " << num;
return 0;
}
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