Ajax Upload image

Question

Q.1 I would like to convert this form to ajax but it seems like my ajax code lacks something. On submit doesn't do anything at all.

Q2. I also want the function to fire on change when the file has been selected not to wait for a submit.

Here is JS.

$('#imageUploadForm').on('submit',(function(e) {
    e.preventDefault()
    $.ajax({
        type:'POST',
        url: $(this).attr('action'),
        data:$(this).serialize(),
        cache:false
    });
}));

and the HTMl with php.

<form name="photo" id="imageUploadForm" enctype="multipart/form-data" action="<?php echo $_SERVER["PHP_SELF"];?>" method="post">
    <input type="file" style="widows:0; height:0" id="ImageBrowse" hidden="hidden" name="image" size="30"/>
    <input type="submit" name="upload" value="Upload" />
    <img width="100" style="border:#000; z-index:1;position: relative; border-width:2px; float:left" height="100px" src="<?php echo $upload_path.$large_image_name.$_SESSION['user_file_ext'];?>" id="thumbnail"/>
</form>

Answer 1

first in your ajax call include success & error function and then check if it gives you error or what?

your code should be like this

$(document).ready(function (e) {     $('#imageUploadForm').on('submit',(function(e) {         e.preventDefault();         var formData = new FormData(this);          $.ajax({             type:'POST',             url: $(this).attr('action'),             data:formData,             cache:false,             contentType: false,             processData: false,             success:function(data){                 console.log("success");                 console.log(data);             },             error: function(data){                 console.log("error");                 console.log(data);             }         });     }));      $("#ImageBrowse").on("change", function() {         $("#imageUploadForm").submit();     }); }); 

Answer 2

HTML Code

<div class="rCol">       <div id ="prv" style="height:auto; width:auto; float:left; margin-bottom: 28px; margin-left: 200px;"></div>        </div>     <div class="rCol" style="clear:both;">      <label > Upload Photo : </label>      <input type="file" id="file" name='file' onChange=" return submitForm();">     <input type="hidden" id="filecount" value='0'> 

Here is Ajax Code:

function submitForm() {      var fcnt = $('#filecount').val();     var fname = $('#filename').val();     var imgclean = $('#file');     if(fcnt<=5)     {     data = new FormData();     data.append('file', $('#file')[0].files[0]);      var imgname  =  $('input[type=file]').val();      var size  =  $('#file')[0].files[0].size;      var ext =  imgname.substr( (imgname.lastIndexOf('.') +1) );     if(ext=='jpg' || ext=='jpeg' || ext=='png' || ext=='gif' || ext=='PNG' || ext=='JPG' || ext=='JPEG')     {      if(size<=1000000)      {     $.ajax({       url: "<?php echo base_url() ?>/upload.php",       type: "POST",       data: data,       enctype: 'multipart/form-data',       processData: false,  // tell jQuery not to process the data       contentType: false   // tell jQuery not to set contentType     }).done(function(data) {        if(data!='FILE_SIZE_ERROR' || data!='FILE_TYPE_ERROR' )        {         fcnt = parseInt(fcnt)+1;         $('#filecount').val(fcnt);         var img = '<div class="dialog" id ="img_'+fcnt+'" ><img src="<?php echo base_url() ?>/local_cdn/'+data+'"><a href="#" id="rmv_'+fcnt+'" onclick="return removeit('+fcnt+')" class="close-classic"></a></div><input type="hidden" id="name_'+fcnt+'" value="'+data+'">';         $('#prv').append(img);         if(fname!=='')         {           fname = fname+','+data;         }else         {           fname = data;         }          $('#filename').val(fname);           imgclean.replaceWith( imgclean = imgclean.clone( true ) );        }        else        {          imgclean.replaceWith( imgclean = imgclean.clone( true ) );          alert('SORRY SIZE AND TYPE ISSUE');        }      });     return false;   }//end size   else   {       imgclean.replaceWith( imgclean = imgclean.clone( true ) );//Its for reset the value of file type     alert('Sorry File size exceeding from 1 Mb');   }   }//end FILETYPE   else   {      imgclean.replaceWith( imgclean = imgclean.clone( true ) );     alert('Sorry Only you can uplaod JPEG|JPG|PNG|GIF file type ');   }   }//end filecount   else   {    imgclean.replaceWith( imgclean = imgclean.clone( true ) );      alert('You Can not Upload more than 6 Photos');   } } 

Here is PHP code :

$filetype = array('jpeg','jpg','png','gif','PNG','JPEG','JPG');    foreach ($_FILES as $key )     {            $name =time().$key['name'];            $path='local_cdn/'.$name;           $file_ext =  pathinfo($name, PATHINFO_EXTENSION);           if(in_array(strtolower($file_ext), $filetype))           {             if($key['name']<1000000)             {               @move_uploaded_file($key['tmp_name'],$path);              echo $name;              }            else            {                echo "FILE_SIZE_ERROR";            }         }         else         {             echo "FILE_TYPE_ERROR";         }// Its simple code.Its not with proper validation. 

Here upload and preview part done.Now if you want to delete and remove image from page and folder both then code is here for deletion. Ajax Part:

function removeit (arg) {        var id  = arg;        // GET FILE VALUE        var fname = $('#filename').val();        var fcnt = $('#filecount').val();         // GET FILE VALUE         $('#img_'+id).remove();        $('#rmv_'+id).remove();        $('#img_'+id).css('display','none');          var dname  =  $('#name_'+id).val();         fcnt = parseInt(fcnt)-1;         $('#filecount').val(fcnt);         var fname = fname.replace(dname, "");         var fname = fname.replace(",,", "");         $('#filename').val(fname);         $.ajax({           url: 'delete.php',           type: 'POST',           data:{'name':dname},           success:function(a){             console.log(a);             }         });     }  

Here is PHP part(delete.php):

$path='local_cdn/'.$_POST['name'];     if(@unlink($path))    {      echo "Success";    }    else    {      echo "Failed";    } 

Answer 3

You can use jquery.form.js plugin to upload image via ajax to the server.

http://malsup.com/jquery/form/

Here is the sample jQuery ajax image upload script

(function() {
$('form').ajaxForm({
    beforeSubmit: function() {  
        //do validation here


    },

    beforeSend:function(){
       $('#loader').show();
       $('#image_upload').hide();
    },
    success: function(msg) {

        ///on success do some here
    }
}); })();  

If you have any doubt, please refer following ajax image upload tutorial here

http://www.smarttutorials.net/ajax-image-upload-using-jquery-php-mysql/