I want to post a form in django using jquery. I want my form to be able to post a file too. Using form.serialize() as I have read wont pass the contents of the file field. So I read about FormData. But when I use FormData my django view won't recognize it as ajax request. My code (using serialize)
$.ajax({
    url:'/customer/create/',
    type: form.attr('method'),
    contentType:'application/x-www-form-urlencoded;charset=utf-8',                    
    dataType:'json',
    data:form.serialize(),
    success:onSuccess,
    error: function(xhr, ajaxOptions, thrownError){
        alert(thrownError + '\n' + xhr.status + '\n' + ajaxOptions);
    }
});
and with form data
fd = new FormData(form)
$.ajax({
    url:'/customer/create/',
    type: form.attr('method'),
    contentType:'multipart/form-data',                    
    dataType:'json',
    data:fd,
    success:onSuccess,
    error: function(xhr, ajaxOptions, thrownError){
        alert(thrownError + '\n' + xhr.status + '\n' + ajaxOptions);
    }
});
Am I missing somethig here? I am not sure this must be the correct contentType. Also mutipart/form-data is set in enctype attribute of the form.
Also I know about jquery-forms, but don't want to use it yet. I only want this to happen at one form of mine so I don't want to load it in my page. I want to see if there is a solution before going there.
I needed to do something like this:
$('#cover_url_file_input').on('change', function(e) {
      var file, imgData;
      file = this.files[0];
      if (file) {
        imgData = new FormData();
        imgData.append('cover_url', file);
        $.ajax({
          type: 'POST',
          url: $('#cover-form').attr('action'),
          data: imgData,
          processData: false,
          contentType: false,
          cache: false,
          success: function(result) {
            if (result.info === 'OK') {
              console.log('OK');
            }
          }
        });
      }
});
                        When using FormData, you need to add processData: false to your jQuery.ajax options so jQuery won't try processing something it cannot.
So do this, and you should be fine:
var form = $('#theForm'),
    fd = new FormData(form[0]);
$.ajax({
    url: '/customer/create/',
    type: form.attr('method'),
    contentType: 'multipart/form-data',                    
    dataType: 'json',
    data: fd,
    processData: false,
    success: onSuccess,
    error: function(xhr, ajaxOptions, thrownError){
        alert(thrownError + '\n' + xhr.status + '\n' + ajaxOptions);
    }
});
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