I am trying to send data to my PHP script to handle some stuff and generate some items.
$.ajax({
type: "POST",
url: "test.php",
data: "album="+ this.title,
success: function(response) {
content.html(response);
}
});
In my PHP file I try to retrieve the album name. Though when I validate it, I created an alert to show what the albumname
is I get nothing, I try to get the album name by $albumname = $_GET['album'];
Though it will say undefined :/
php $userAnswer = $_POST['name']; $sql="SELECT * FROM <tablename> where color='". $userAnswer. "'" ; $result=mysql_query($sql); $row=mysql_fetch_array($result); // for first row only and suppose table having data echo json_encode($row); // pass array in json_encode ?>
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You are sending a POST AJAX request so use $albumname = $_POST['album'];
on your server to fetch the value. Also I would recommend you writing the request like this in order to ensure proper encoding:
$.ajax({
type: 'POST',
url: 'test.php',
data: { album: this.title },
success: function(response) {
content.html(response);
}
});
or in its shorter form:
$.post('test.php', { album: this.title }, function() {
content.html(response);
});
and if you wanted to use a GET request:
$.ajax({
type: 'GET',
url: 'test.php',
data: { album: this.title },
success: function(response) {
content.html(response);
}
});
or in its shorter form:
$.get('test.php', { album: this.title }, function() {
content.html(response);
});
and now on your server you wil be able to use $albumname = $_GET['album'];
. Be careful though with AJAX GET requests as they might be cached by some browsers. To avoid caching them you could set the cache: false
setting.
You can also use bellow code for pass data using ajax.
var dataString = "album" + title;
$.ajax({
type: 'POST',
url: 'test.php',
data: dataString,
success: function(response) {
content.html(response);
}
});
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