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Affine transformation between contours in OpenCV

Tags:

python

opencv

I have a historical time sequence of seafloor images scanned from film that need registration.

from pylab import *
import cv2
import urllib

urllib.urlretrieve('http://geoport.whoi.edu/images/frame014.png','frame014.png');
urllib.urlretrieve('http://geoport.whoi.edu/images/frame015.png','frame015.png');

gray1=cv2.imread('frame014.png',0)
gray2=cv2.imread('frame015.png',0)
figure(figsize=(14,6))
subplot(121);imshow(gray1,cmap=cm.gray);
subplot(122);imshow(gray2,cmap=cm.gray);

enter image description here

I want to use the black region on the left of each image to do the registration, since that region was inside the camera and should be fixed in time. So I just need to compute the affine transformation between the black regions.

I determined these regions by thresholding and finding the largest contour:

def find_biggest_contour(gray,threshold=40):
    # threshold a grayscale image 
    ret,thresh = cv2.threshold(gray,threshold,255,1)
    # find the contours
    contours,h = cv2.findContours(thresh,mode=cv2.RETR_LIST,method=cv2.CHAIN_APPROX_NONE)
    # measure the perimeter
    perim = [cv2.arcLength(cnt,True) for cnt in contours]
    # find contour with largest perimeter
    i=perim.index(max(perim))
    return contours[i]

c1=find_biggest_contour(gray1)
c2=find_biggest_contour(gray2)

x1=c1[:,0,0];y1=c1[:,0,1]
x2=c2[:,0,0];y2=c2[:,0,1]

figure(figsize=(8,8))
imshow(gray1,cmap=cm.gray, alpha=0.5);plot(x1,y1,'b-')
imshow(gray2,cmap=cm.gray, alpha=0.5);plot(x2,y2,'g-')
axis([0,1500,1000,0]);

enter image description here

The blue is the longest contour from the 1st frame, the green is the longest contour from the 2nd frame.

What is the best way to determine the rotation and offset between the blue and green contours?

I only want to use the right side of the contours in some region surrounding the step, something like the region between the arrows.

Of course, if there is a better way to register these images, I'd love to hear it. I already tried a standard feature matching approach on the raw images, and it didn't work well enough.

like image 282
Rich Signell Avatar asked Apr 12 '13 19:04

Rich Signell


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2 Answers

Following Shambool's suggested approach, here's what I've come up with. I used a Ramer-Douglas-Peucker algorithm to simplify the contour in the region of interest and identified the two turning points. I was going to use the two turning points to get my three unknowns (xoffset, yoffset and angle of rotation), but the 2nd turning point is a bit too far toward the right because RDP simplified away the smoother curve in this region. So instead I used the angle of the line segment leading up to the 1st turning point. Differencing this angle between image1 and image2 gives me the rotation angle. I'm still not completely happy with this solution. It worked well enough for these two images, but I'm not sure it will work well on the entire image sequence. We'll see.

It would really be better to fit the contour to the known shape of the black border.

# select region of interest from largest contour 
ind1=where((x1>190.) & (y1>200.) & (y1<900.))[0]
ind2=where((x2>190.) & (y2>200.) & (y2<900.))[0]
figure(figsize=(10,10))
imshow(gray1,cmap=cm.gray, alpha=0.5);plot(x1[ind1],y1[ind1],'b-')
imshow(gray2,cmap=cm.gray, alpha=0.5);plot(x2[ind2],y2[ind2],'g-')
axis([0,1500,1000,0])

enter image description here

def angle(x1,y1):
    #  Returns angle of each segment along an (x,y) track
    return array([math.atan2(y,x) for (y,x) in zip(diff(y1),diff(x1))])

def simplify(x,y, tolerance=40, min_angle = 60.*pi/180.): 
    """
    Use the Ramer-Douglas-Peucker algorithm to simplify the path
    http://en.wikipedia.org/wiki/Ramer-Douglas-Peucker_algorithm
    Python implementation: https://github.com/sebleier/RDP/
    """
    from RDP import rdp   
    points=vstack((x,y)).T
    simplified = array(rdp(points.tolist(), tolerance))
    sx, sy = simplified.T

    theta=abs(diff(angle(sx,sy)))
    # Select the index of the points with the greatest theta
    # Large theta is associated with greatest change in direction.
    idx = where(theta>min_angle)[0]+1
    return sx,sy,idx

sx1,sy1,i1 = simplify(x1[ind1],y1[ind1])
sx2,sy2,i2 = simplify(x2[ind2],y2[ind2])
fig = plt.figure(figsize=(10,6))
ax =fig.add_subplot(111)

ax.plot(x1, y1, 'b-', x2, y2, 'g-',label='original path')
ax.plot(sx1, sy1, 'ko-', sx2, sy2, 'ko-',lw=2, label='simplified path')
ax.plot(sx1[i1], sy1[i1], 'ro', sx2[i2], sy2[i2], 'ro', 
    markersize = 10, label='turning points')
ax.invert_yaxis()
plt.legend(loc='best')

enter image description here

# determine x,y offset between 1st turning points, and 
# angle from difference in slopes of line segments approaching 1st turning point
xoff = sx2[i2[0]] - sx1[i1[0]]
yoff = sy2[i2[0]] - sy1[i1[0]]
iseg1 = [i1[0]-1, i1[0]]
iseg2 = [i2[0]-1, i2[0]]
ang1 = angle(sx1[iseg1], sy1[iseg1])
ang2 = angle(sx2[iseg2], sy2[iseg2])
ang = -(ang2[0] - ang1[0])
print xoff, yoff, ang*180.*pi

-28 14 5.07775871644

# 2x3 affine matrix M
M=array([cos(ang),sin(ang),xoff,-sin(ang),cos(ang),yoff]).reshape(2,3)
print M

[[  9.99959685e-01   8.97932821e-03  -2.80000000e+01]
 [ -8.97932821e-03   9.99959685e-01   1.40000000e+01]]

# warp 2nd image into coordinate frame of 1st
Minv = cv2.invertAffineTransform(M)
gray2b = cv2.warpAffine(gray2,Minv,shape(gray2.T))

figure(figsize=(10,10))
imshow(gray1,cmap=cm.gray, alpha=0.5);plot(x1[ind1],y1[ind1],'b-')
imshow(gray2b,cmap=cm.gray, alpha=0.5);
axis([0,1500,1000,0]);
title('image1 and transformed image2 overlain with 50% transparency');

enter image description here

like image 60
Rich Signell Avatar answered Sep 19 '22 13:09

Rich Signell


Good question.

One approach is to represent contours as 2d point clouds and then do registration. More simple and clear code in Matlab that can give you affine transform.

And more complex C++ code(using VXL lib) with python and matlab wrapper included. Or you can use some modificated ICP(iterative closest point) algorithm that is robust to noise and can handle affine transform.

Also your contours seems to be not very accurate so it can be a problem.

Another approach is to use some kind of registration that use pixel values. Matlab code (I think it's using some kind of minimizer+ crosscorrelation metric) Also maybe there is some kind of optical flow registration(or some other kind) that is used in medical imaging.

Also you can use point features as SIFT(SURF).

You can try it quick in FIJI(ImageJ) also this link.

  1. Open 2 images
  2. Plugins->feature extraction-> sift (or other)
  3. Set expected transformation to affine
  4. Look at estimated transformation model [3,3] homography matrix in ImageJ log. If it works good then you can implement it in python using OpenCV or maybe using Jython with ImageJ.

And it will be better if you post original images and describe all conditions (it seems that image is changing between frames)

like image 45
mrgloom Avatar answered Sep 16 '22 13:09

mrgloom