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AES in ASP.NET with VB.NET

What is a good link or article on encrypting a URL link with AES to pass username to another web site in ASP.NET using VB.NET 2005? FYI: The receiving web site will have access to the private KEY to decrypt.

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user80687 Avatar asked Dec 02 '22 07:12

user80687


2 Answers

First

Don't do it! Writing your own crypto system can easily lead to making mistakes. It's best to use an existing system, or if not, get someone who knows cryptography to do it. If you have to do it yourself, read Practical Cryptography.

And please, remember: "We already have enough fast, insecure systems." (Bruce Schneier) -- Do things correct and worry about performance later.

That said, if you are stuck on using AES to roll your own, here are a few pointers.

Initialization Vector

AES is a block cipher. Given a key and a block of plaintext, it converts it to a specific ciphertext. The problem with this is that the same blocks of data will generate the same ciphertext with the same key, every time. So suppose you send data like this:

user=Encrypt(Username)&roles=Encrypt(UserRoles)

They're two separate blocks, and the UserRoles encryption will have the same ciphertext each time, regardless of the name. All I need is the ciphertext for an admin, and I can drop it right in with my cipher'd username. Oops.

So, there are cipher operation modes. The main idea is that you'll take the ciphertext of one block, and XOR it into the ciphertext of the next block. That way we'll do Encrypt(UserRoles, Username), and the Username ciphertext is affected by the UserRoles.

The problem is that the first block is still vulnerable - just by seeing someone's ciphertext, I might know their roles. Enter the initialization vector. The IV "starts up" the cipher and ensures it has random data to encrypt the rest of the stream. So now the UserRoles ciphertext has the ciphertext of the random IV XOR'd in. Problem solved.

So, make sure you generate a random IV for each message. The IV is not sensitive and can be sent plaintext with the ciphertext. Use an IV large enough -- the size of the block should be fine for many cases.

Integrity

AES doesn't provide integrity features. Anyone can modify your ciphertext, and the decrypt will still work. It's unlikely it'll be valid data in general, but it might be hard to know what valid data is. For instance, if you're transmitting a GUID encrypted, it'd be easy to modify some bits and generate a completely different one. That could lead to application errors and so on.

The fix there is to run a hash algorithm (use SHA256 or SHA512) on the plaintext, and include that in the data you transmit. So if my message is (UserName, Roles), you'll send (UserName, Roles, Hash(UserName, Roles)). Now if someone tampers with the ciphertext by flipping a bit, the hash will no longer compute and you can reject the message.

Key derivation

If you need to generate a key from a password, use the built-in class: System.Security.Cryptography.PasswordDeriveBytes. This provides salting and iterations, which can improve the strength of derived keys and reduce the chance of discovering the password if the key is compromised.

Timing/replay

Edit: Sorry for not mentioning this earlier :P. You also need to make sure you have an anti-replay system. If you simply encrypt the message and pass it around, anyone who gets the message can just resend it. To avoid this, you should add a timestamp to the message. If the timestamp is different by a certain threshold, reject the message. You may also want to include a one-time ID with it (this could be the IV) and reject time-valid messages that come from other IPs using the same ID.

It's important to make sure you do the hash verification when you include the timing information. Otherwise, someone could tamper with a bit of the ciphertext and potentially generate a valid timestamp if you don't detect such brute force attempts.

Sample code

Since apparently using an IV correctly is controversial for some folks, here's some code that'll generate random IVs and add them to your output for you. It'll also perform the authentication step, making sure the encrypted data wasn't modified.

using System;
using System.Security.Cryptography;
using System.Text;

class AesDemo {

    const int HASH_SIZE = 32; //SHA256

    /// <summary>Performs encryption with random IV (prepended to output), and includes hash of plaintext for verification.</summary>
    public static byte[] Encrypt(string password, byte[] passwordSalt, byte[] plainText) {
        // Construct message with hash
        var msg = new byte[HASH_SIZE + plainText.Length];
        var hash = computeHash(plainText, 0, plainText.Length);
        Buffer.BlockCopy(hash, 0, msg, 0, HASH_SIZE);
        Buffer.BlockCopy(plainText, 0, msg, HASH_SIZE, plainText.Length);

        // Encrypt
        using (var aes = createAes(password, passwordSalt)) {
            aes.GenerateIV();
            using (var enc = aes.CreateEncryptor()) {

                var encBytes = enc.TransformFinalBlock(msg, 0, msg.Length);
                // Prepend IV to result
                var res = new byte[aes.IV.Length + encBytes.Length];
                Buffer.BlockCopy(aes.IV, 0, res, 0, aes.IV.Length);
                Buffer.BlockCopy(encBytes, 0, res, aes.IV.Length, encBytes.Length);
                return res;
            }
        }
    }

    public static byte[] Decrypt(string password, byte[] passwordSalt, byte[] cipherText) {
        using (var aes = createAes(password, passwordSalt)) {
            var iv = new byte[aes.IV.Length];
            Buffer.BlockCopy(cipherText, 0, iv, 0, iv.Length);
            aes.IV = iv; // Probably could copy right to the byte array, but that's not guaranteed

            using (var dec = aes.CreateDecryptor()) {
                var decBytes = dec.TransformFinalBlock(cipherText, iv.Length, cipherText.Length - iv.Length);

                // Verify hash
                var hash = computeHash(decBytes, HASH_SIZE, decBytes.Length - HASH_SIZE);
                var existingHash = new byte[HASH_SIZE];
                Buffer.BlockCopy(decBytes, 0, existingHash, 0, HASH_SIZE);
                if (!compareBytes(existingHash, hash)){
                    throw new CryptographicException("Message hash incorrect.");
                }

                // Hash is valid, we're done
                var res = new byte[decBytes.Length - HASH_SIZE];
                Buffer.BlockCopy(decBytes, HASH_SIZE, res, 0, res.Length);
                return res;
            }
        }
    }

    static bool compareBytes(byte[] a1, byte[] a2) {
        if (a1.Length != a2.Length) return false;
        for (int i = 0; i < a1.Length; i++) {
            if (a1[i] != a2[i]) return false;
        }
        return true;
    }

    static Aes createAes(string password, byte[] salt) {
        // Salt may not be needed if password is safe
        if (password.Length < 8) throw new ArgumentException("Password must be at least 8 characters.", "password");
        if (salt.Length < 8) throw new ArgumentException("Salt must be at least 8 bytes.", "salt");
        var pdb = new PasswordDeriveBytes(password, salt, "SHA512", 129);
        var key = pdb.GetBytes(16);

        var aes = Aes.Create();
        aes.Mode = CipherMode.CBC;
        aes.Key = pdb.GetBytes(aes.KeySize / 8);
        return aes;
    }

    static byte[] computeHash(byte[] data, int offset, int count) {
        using (var sha = SHA256.Create()) {
            return sha.ComputeHash(data, offset, count);
        }
    }

    public static void Main() {
        var password = "1234567890!";
        var salt = new byte[] { 1, 2, 3, 4, 5, 6, 7, 8, 9, 0 };
        var ct1 = Encrypt(password, salt, Encoding.UTF8.GetBytes("Alice; Bob; Eve;: PerformAct1"));
        Console.WriteLine(Convert.ToBase64String(ct1));
        var ct2 = Encrypt(password, salt, Encoding.UTF8.GetBytes("Alice; Bob; Eve;: PerformAct2"));
        Console.WriteLine(Convert.ToBase64String(ct2));

        var pt1 = Decrypt(password, salt, ct1);
        Console.WriteLine(Encoding.UTF8.GetString(pt1));
        var pt2 = Decrypt(password, salt, ct2);
        Console.WriteLine(Encoding.UTF8.GetString(pt2));

        // Now check tampering
        try {
            ct1[30]++;
            Decrypt(password, salt, ct1);
            Console.WriteLine("Error: tamper detection failed.");
        } catch (Exception ex) {
            Console.WriteLine("Success: tampering detected.");
            Console.WriteLine(ex.ToString());
        }
    }
}

Output:

JZVaD327sDmCmdzY0PsysnRgHbbC3eHb7YXALb0qxFVlr7Lkj8WaOZWc1ayWCvfhTUz/y0QMz+uv0PwmuG8VBVEQThaNTD02JlhIs1DjJtg= QQvDujNJ31qTu/foDFUiVMeWTU0jKL/UJJfFAvmFtz361o3KSUlk/zH+4701mlFEU4Ce6VuAAuaiP1EENBJ74Wc8mE/QTofkUMHoa65/5e4= Alice; Bob; Eve;: PerformAct1 Alice; Bob; Eve;: PerformAct2 Success: tampering detected. System.Security.Cryptography.CryptographicException: Message hash incorrect. at AesDemo.Decrypt(String password, Byte[] passwordSalt, Byte[] cipherText) in C:\Program.cs:line 46 at AesDemo.Main() in C:\Program.cs:line 100

After removing the random IV and the hash, here's the type of output:

tZfHJSFTXYX8V38AqEfYVXU5Dl/meUVAond70yIKGHY= tZfHJSFTXYX8V38AqEfYVcf9a3U8vIEk1LuqGEyRZXM=

Notice how the first block, corresponding to "Alice; Bob; Eve;" is the same. "Corner case" indeed.

Example without hashing

Here's a simple example of passing a 64-bit integer. Just encrypt and you're open to attack. In fact, the attack is easily done, even with CBC padding.

public static void Main() {
    var buff = new byte[8];
    new Random().NextBytes(buff);
    var v = BitConverter.ToUInt64(buff, 0);
    Console.WriteLine("Value: " + v.ToString());
    Console.WriteLine("Value (bytes): " + BitConverter.ToString(BitConverter.GetBytes(v)));
    var aes = Aes.Create();
    aes.GenerateIV();
    aes.GenerateKey();
    var encBytes = aes.CreateEncryptor().TransformFinalBlock(BitConverter.GetBytes(v), 0, 8);
    Console.WriteLine("Encrypted: " + BitConverter.ToString(encBytes));
    var dec = aes.CreateDecryptor();
    Console.WriteLine("Decrypted: " + BitConverter.ToUInt64(dec.TransformFinalBlock(encBytes, 0, encBytes.Length), 0));
    for (int i = 0; i < 8; i++) {
        for (int x = 0; x < 250; x++) {
            encBytes[i]++;
            try {
                Console.WriteLine("Attacked: " + BitConverter.ToUInt64(dec.TransformFinalBlock(encBytes, 0, encBytes.Length), 0));
                return;
            } catch { }
        }
    }
}

Output:

Value: 6598637501946607785 Value

(bytes): A9-38-19-D1-D8-11-93-5B

Encrypted:

31-59-B0-25-FD-C5-13-D7-81-D8-F5-8A-33-2A-57-DD

Decrypted: 6598637501946607785

Attacked: 14174658352338201502

So, if that's the kind of ID you're sending, it could quite easily be changed to another value. You need to authenticate outside of your message. Sometimes, the message structure is unlikely to fall into place and can sorta act as a safeguard, but why rely on something that could possibly change? You need to be able to rely on your crypto working correctly regardless of the application.

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MichaelGG Avatar answered Dec 04 '22 01:12

MichaelGG


I wrote a blog post which has a sample project that you can download here (C# though): http://www.codestrider.com/blog/read/AESFileEncryptorWithRSAEncryptedKeys.aspx

The code basically uses AES for encryption of binary data and then RSA encrypts the Key and the IV using an X509Certificate. So, as long as the private key certificate is available, the Key and IV can be decrypted, and then in turn the AES encrypted data can be decrypted ..

You could set up your certificate stores so that the 'encryptor' only has access to the public key certificate, while the 'decryptor' has access to the private key.

This allows you to encrypt using different Key and IV each time and avoid hardcoding anything.. which I believe is more secure. There should be nothing in your source code that would easily allow someone to decrypt your data - and if your system was ever compromised, you would only need to swap out the certificates with new ones. No need to recompile the application with new hardcoded values.. :)

The sample code may be slightly different from your intended use, but I think the technique and some of the code might be useful to you.

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markt Avatar answered Dec 04 '22 02:12

markt