I have just started learning R and I wrote this code to learn on functions and loops.
squared<-function(x){
  m<-c()
  for(i in 1:x){
    y<-i*i
    c(m,y)
  }
  return (m)
}
squared(5)  
NULL  
Why does this return NULL. I want i*i values to append to the end of mand return a vector. Can someone please point out whats wrong with this code.
You haven't put anything inside m <- c() in your loop since you did not use an assignment. You are getting the following -
m <- c()
m
# NULL
You can change the function to return the desired values by assigning m in the loop.
squared <- function(x) {
    m <- c()
    for(i in 1:x) {
        y <- i * i
        m <- c(m, y)
    }
    return(m)
}
squared(5)
# [1]  1  4  9 16 25
But this is inefficient because we know the length of the resulting vector will be 5 (or x).  So we want to allocate the memory first before looping.  This will be the better way to use the for() loop.
squared <- function(x) {
    m <- vector("integer", x)
    for(i in seq_len(x)) {
        m[i] <- i * i
    }
    m
}
squared(5)
# [1]  1  4  9 16 25 
Also notice that I have removed return() from the second function. It is not necessary there, so it can be removed.  It's a matter of personal preference to leave it in this situation.  Sometimes it will be necessary, like in if() statements for example.
I know the question is about looping, but I also must mention that this can be done more efficiently with seven characters using the primitive ^, like this
(1:5)^2
# [1]  1  4  9 16 25
^ is a primitive function, which means the code is written entirely in C and will be the most efficient of these three methods
`^`
# function (e1, e2)  .Primitive("^")
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