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Try this: printf '\n%s\n' 'I want this on a new line! ' That allows you to separate the formatting from the actual text.
The printf statement does not automatically append a newline to its output. It outputs only what the format string specifies. So if a newline is needed, you must include one in the format string.
In most C compilers, including ours, the newline escape sequence '\n' yields an ASCII line feed character. The C escape sequence for a carriage return is '\r'.
Using %c to print the new line We can use the %c within the string in printf() statement with the value 0x0A, 10 or '\n'.
For some reason, adding \n to printf() changes the behaviour of below code. The code without \n prints (null) whereas the code with \n leads to Segmentation fault.
Printf.c
#include <stdio.h> int main(int argc, char* argv[]){ printf("%s", argv[1]); } Printf.c - Output
$ gcc -o Printf Printf.c $ ./Printf (null) Printf_Newline.c
#include <stdio.h> int main(int argc, char* argv[]){ printf("%s\n", argv[1]); } Printf_Newline.c - Output
$ gcc -o Printf_Newline Printf_Newline.c $ ./Printf_Newline Segmentation fault (core dumped) I am curious to understand the reason behind this.
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