Add Dynamic Content Disposition for file names(amazon S3) in python

Question

I have a Django model that saves filename as "uuid4().pdf". Where uuid4 generates a random uuid for each instance created. This file name is also stored on the amazon s3 server with the same name.

I am trying to add a custom disposition for filename that i upload to amazon s3, this is because i want to see a custom name whenever i download the file not the uuid one. At the same time, i want the files to stored on s3 with the uuid filename.

So, I am using django-storages with python 2.7. I have tried adding content_disposition in settings like this:

AWS_CONTENT_DISPOSITION = 'core.utils.s3.get_file_name'

where get_file_name() returns the filename.

I have also tried adding this to the settings:

AWS_HEADERS = {
'Content-Disposition': 'attachments; filename="%s"'% get_file_name(),

 }

no luck!

Do anyone of you know to implement this.

Answer 1

Current version of S3Boto3Storage from django-storages supports AWS_S3_OBJECT_PARAMETERS global settings variable, which allows modify ContentDisposition too. But the problem is that it is applied as is to all objects that are uploaded to s3 and, moreover, affects all models working with the storage, which may turn to be not the expected result.

The following hack worked for me.

from storages.backends.s3boto3 import S3Boto3Storage

class DownloadableS3Boto3Storage(S3Boto3Storage):

    def _save_content(self, obj, content, parameters):
        """
        The method is called by the storage for every file being uploaded to S3.
        Below we take care of setting proper ContentDisposition header for
        the file.
        """
        filename = obj.key.split('/')[-1]
        parameters.update({'ContentDisposition': f'attachment; filename="{filename}"'})
        return super()._save_content(obj, content, parameters)

Here we override native save method of the storage object and make sure proper content disposition is set on each file. Of course, you need to feed this storage to the field you working on:

my_file_filed = models.FileField(upload_to='mypath', storage=DownloadableS3Boto3Storage())