I have a rails 3 app with the ActiveAdmin gem. My goal is to make a custom controller rendering in custom views which keep it layout.
I succeeded to make a custom controller rendering in custom views with this code :
pages.rb :
ActiveAdmin.register_page 'Pages' do
content only: :index do
render 'index'
end
content only: :edit do
render partial: 'edit'
end
controller do
def index
@search = Page.includes(:translations).where("page_translations.locale='fr'").metasearch(params[:search])
@pages = @search.page params[:page]
end
def edit
@page = Page.find params[:id]
end
end
end
And for example my index.html.erb file :
<h1>Pages</h1>
<%= form_for @search, :url => admin_pages_path, :html => {:method => :get, :class => "form-inline" } do |f| %>
<%= f.text_field :translations_name_contains , :class => "search-query input-medium focused" %>
<%= f.submit("Search", :class => "btn btn-primary") %>
<% end %>
<table>
<thead>
<tr>
<th><%= sort_link @search, :translations_name, "Titre" %></th>
<th><%= sort_link @search, :permalink, "Permalien" %></th>
<th>Actions</th>
</tr>
</thead>
<tbody>
<% @pages.each do |page| %>
<tr>
<td><%= page.name %></td>
<td><%= page.permalink %></td>
<td><%= link_to("Update",edit_admin_page_path(page)) %></td>
</tr>
<% end %>
</tbody>
</table>
Is there a means to keep the ActiveAdmin layout ?
Problem solved. Just add layout 'active_admin'
to your code :
controller do
layout 'active_admin' # <-- here
def index
@search = Page.includes(:translations).where("page_translations.locale='fr'").metasearch(params[:search])
@pages = @search.page params[:page]
end
def edit
@page = Page.find params[:id]
end
end
code is here : for model less view with admin layout
ActiveAdmin.register_page "myname" do
content only: :index do
render 'index'
end
controller do
def index
end
end
end
Then add views under app/views/admin/myname/ as _index.html.erb
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