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Accessing private members from powershell

Tags:

powershell

I'm trying to get Uri to stop encoding '/' As explained here: GETting a URL with an url-encoded slash

But how to achieve the same in powershell ?

I'm trying to follow the route of accessing private property and changing it's value but I can't get it to work.

[Uri].GetProperties([System.Reflection.BindingFlags]::NonPublic) - returns nothing

Any ideas?

like image 492
Jammes Avatar asked Oct 03 '12 13:10

Jammes


3 Answers

This is working solution for PowerShell:

$uri = [Uri]"http://example.com/%2F"
# access the .PathAndQuery field to initialize the Uri object
$pathAndQuery = $uri.PathAndQuery
$flagsField = $uri.GetType().GetField("m_Flags", [Reflection.BindingFlags]::NonPublic -bor [Reflection.BindingFlags]::Instance)
$flagsValue = [UInt64]$flagsField.GetValue($uri)
# remove flags Flags.PathNotCanonical and Flags.QueryNotCanonical
$flagsValue = [UInt64]($flagsValue -band (-bnot 0x30));
$flagsField.SetValue($uri, $flagsValue)
Write-Host $uri.AbsoluteUri

Thanks to google-api-dotnet-client path :-) please note, that there is some difference with .net 2.0, my code is working for > .net 2.0 (for <= 2.0 versions, the type of flagsValue object will be [Int32] instead of [Uint64])

like image 192
Boo Avatar answered Nov 03 '22 02:11

Boo


try this (like in your link):

$uri.GetType().GetField("m_Flags", [System.Reflection.BindingFlags]::Instance -bor `
 [System.Reflection.BindingFlags]::NonPublic)

to get non public properties:

$uri.GetType().GetProperties( [System.Reflection.BindingFlags]::Instance -bor `
[System.Reflection.BindingFlags]::NonPublic )
like image 37
CB. Avatar answered Nov 03 '22 01:11

CB.


Taking that other post as what you need, you want this:

$uri = [uri]"http://example.com/%2F"
$f = [uri].getfield("m_Flags", "nonpublic,instance")
$v = [int]($f.getvalue($uri))
$f.setvalue($uri, [uint64]($v -band (-bnot 0x30)))

PowerShell's -bnot and -band bitwise operators don't work with any types bigger than [int] so I'm downcasting to [int] which does not overflow for the above case (which means flag values beyond [int]::maxvalue are not present.)

like image 23
x0n Avatar answered Nov 03 '22 02:11

x0n