I wrote a new combinator for my parser in scala.
Its a variation of the ^^ combinator, which passes position information on. But accessing the position information of the input element really cost performance.
In my case parsing a big example need around 3 seconds without position information, with it needs over 30 seconds.
I wrote a runnable example where the runtime is about 50% more when accessing the position.
Why is that? How can I get a better runtime?
Example:
import scala.util.parsing.combinator.RegexParsers
import scala.util.parsing.combinator.Parsers
import scala.util.matching.Regex
import scala.language.implicitConversions
object FooParser extends RegexParsers with Parsers {
var withPosInfo = false
def b: Parser[String] = regexB("""[a-z]+""".r) ^^@ { case (b, x) => b + " ::" + x.toString }
def regexB(p: Regex): BParser[String] = new BParser(regex(p))
class BParser[T](p: Parser[T]) {
def ^^@[U](f: ((Int, Int), T) => U): Parser[U] = Parser { in =>
val source = in.source
val offset = in.offset
val start = handleWhiteSpace(source, offset)
val inwo = in.drop(start - offset)
p(inwo) match {
case Success(t, in1) =>
{
var a = 3
var b = 4
if(withPosInfo)
{ // takes a lot of time
a = inwo.pos.line
b = inwo.pos.column
}
Success(f((a, b), t), in1)
}
case ns: NoSuccess => ns
}
}
}
def main(args: Array[String]) = {
val r = "foo"*50000000
var now = System.nanoTime
parseAll(b, r)
var us = (System.nanoTime - now) / 1000
println("without: %d us".format(us))
withPosInfo = true
now = System.nanoTime
parseAll(b, r)
us = (System.nanoTime - now) / 1000
println("with : %d us".format(us))
}
}
Output:
without: 2952496 us
with : 4591070 us
Unfortunately, I don't think you can use the same approach. The problem is that line numbers end up implemented by scala.util.parsing.input.OffsetPosition
which builds a list of every line break every time it is created. So if it ends up with string input it will parse the entire thing on every call to pos
(twice in your example). See the code for CharSequenceReader and OffsetPosition for more details.
There is one quick thing you can do to speed this up:
val ip = inwo.pos
a = ip.line
b = ip.column
to at least avoid creating pos
twice. But that still leaves you with a lot of redundant work. I'm afraid to really solve the problem you'll have to build the index as in OffsetPosition
yourself, just once, and then keep referring to it.
You could also file a bug report / make an enhancement request. This is not a very good way to implement the feature.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With