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Accessing an attribute of a multiprocessing Proxy of a class

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I have a class that I want to share in a read-only fashion with children processes in a pool, so I prepared a proxy of a class but it didn't work. The following is a simplified example of my problem.

from multiprocessing.managers import BaseManager  class TestClass:     def __init__(self, a):         self.a = a     def b(self):         print self.a  class MyManager(BaseManager): pass  MyManager.register('test', TestClass)  if __name__ == '__main__':     manager = MyManager()     manager.start()     t = TestClass(1)     print t.a     mt = manager.test(2)     mt.b()     mt.a 

When I run this code I get:

1 2 Traceback (most recent call last):   File "multiprocess_example_stackexchange.py", line 20, in <module>     mt.a  AttributeError: 'AutoProxy[test]' object has no attribute 'a' 

It seems that I cannot access the attribute of a shared object directly via a proxy. Is the only way using a method that gets the attribute, or am I doing something wrong?

like image 889
Chan Y. Park Avatar asked Oct 22 '14 02:10

Chan Y. Park


1 Answers

The Proxy objects used by multiprocessing.BaseManager and its sub-classes normally only expose methods from the objects they're referring to, not attributes. Now, there is multiprocessing.Manager().Namespace, which provides a Proxy sub-class that does provide access to attributes, rather than methods. We can create our own Proxy type which inherits from that, which enables access to all our attributes, as well as access to our b function:

from multiprocessing.managers import BaseManager, NamespaceProxy  class TestClass(object):     def __init__(self, a):         self.a = a      def b(self):         print self.a  class MyManager(BaseManager): pass  class TestProxy(NamespaceProxy):     # We need to expose the same __dunder__ methods as NamespaceProxy,     # in addition to the b method.     _exposed_ = ('__getattribute__', '__setattr__', '__delattr__', 'b')      def b(self):         callmethod = object.__getattribute__(self, '_callmethod')         return callmethod('b')  MyManager.register('test', TestClass, TestProxy)  if __name__ == '__main__':     manager = MyManager()     manager.start()     t = TestClass(1)     print t.a     mt = manager.test(2)     print mt.a     mt.a = 5     mt.b() 

Output:

1 2 5 

Edit:

If you want to be able to dynamically add methods from your original class to a Proxy class, you can do something like this:

from multiprocessing.managers import BaseManager, NamespaceProxy import inspect  class TestClass(object):     def __init__(self, a):         self.a = a      def b(self):         print self.a  class AnotherClass(object):     def __init__(self, a):         self.a = a      def c(self):         print self.a  class MyManager(BaseManager): pass  class ProxyBase(NamespaceProxy):     _exposed_ = ('__getattribute__', '__setattr__', '__delattr__')  class TestProxy(ProxyBase): pass class AnotherProxy(ProxyBase): pass   def register_proxy(name, cls, proxy):     for attr in dir(cls):         if inspect.ismethod(getattr(cls, attr)) and not attr.startswith("__"):             proxy._exposed_ += (attr,)             setattr(proxy, attr,                      lambda s: object.__getattribute__(s, '_callmethod')(attr))     MyManager.register(name, cls, proxy)  register_proxy('test', TestClass, TestProxy) register_proxy('another', AnotherClass, AnotherProxy)  if __name__ == '__main__':     manager = MyManager()     manager.start()     mt = manager.test(2)     ma = manager.another(3)     mt.b()     ma.c()     mt.a = 5     ma.a = 6     mt.b()     ma.c() 
like image 194
dano Avatar answered Sep 20 '22 17:09

dano