I know how to access elements in a vector by indices doing:
test = numpy.array([1,2,3,4,5,6])
indices = list([1,3,5])
print(test[indices])
which gives the correct answer : [2 4 6]
But I am trying to do the same thing using a 2D matrix, something like:
currentGrid = numpy.array( [[0, 0.1],
[0.9, 0.9],
[0.1, 0.1]])
indices = list([(0,0),(1,1)])
print(currentGrid[indices])
this should display me "[0.0 0.9]" for the value at (0,0) and the one at (1,1) in the matrix. But instead it displays "[ 0.1 0.1]". Also if I try to use 3 indices with :
indices = list([(0,0),(1,1),(0,2)])
I now get the following error:
Traceback (most recent call last):
File "main.py", line 43, in <module>
print(currentGrid[indices])
IndexError: too many indices for array
I ultimately need to apply a simple max() operation on all the elements at these indices and need the fastest way to do that for optimization purposes.
What am I doing wrong ? How can I access specific elements in a matrix to do some operation on them in a very efficient way (not using list comprehension nor a loop).
The data elements in a matrix can be accessed by using the indexes. The access method is same as the way data is accessed in Two dimensional array.
nonzero() function is used to Compute the indices of the elements that are non-zero. It returns a tuple of arrays, one for each dimension of arr, containing the indices of the non-zero elements in that dimension. The corresponding non-zero values in the array can be obtained with arr[nonzero(arr)] .
The problem is the arrangement of the indices you're passing to the array. If your array is two-dimensional, your indices must be two lists, one containing the vertical indices and the other one the horizontal ones. For instance:
idx_i, idx_j = zip(*[(0, 0), (1, 1), (0, 2)])
print currentGrid[idx_j, idx_i]
# [0.0, 0.9, 0.1]
Note that the first element when indexing arrays is the last dimension, e.g.: (y, x). I assume you defined yours as (x, y) otherwise you'll get an IndexError
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