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On My Python 2.6 ( 64bit, win7, ActivePython ), when i call: os.path.abspath('D:/PROJECTS/SuiShouBei/www/ssb/static/voices/en/mp3/con.mp3')
It returns:'\\\\.\\con'
I have no problem with other paths so far.
Anyone has the same issue?
Can someone please tell me why?
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According to docs os. path. abspath() returns a normalized absolutized version of the pathname path which may sound fancy but it simply means that this method returns the pathname to the path passed as a parameter to this function.
abspath (path) Return a normalized absolutized version of the pathname path. On most platforms, this is equivalent to calling the function normpath() as follows: normpath(join(os.getcwd(), path)) . Changed in version 3.6: Accepts a path-like object.
I can reproduce this in Python 2.6, 2.7, 3.1 and 3.2.
The reason for this behavior is the fact that CON is an illegal filename in Windows (try os.path.abspath('D:/PROJECTS/SuiShouBei/www/ssb/static/voices/en/mp3/cont.mp3') and see that everything works fine).
So take care that your filenames don't contain
< (less than) > (greater than) : (colon) " (double quote) / (forward slash) \ (backslash) | (vertical bar or pipe) ? (question mark) * (asterisk) Also do not use the following reserved device names for the name of a file (with or without extension):
CON, PRN, AUX, NUL, COM1, COM2, COM3, COM4, COM5, COM6, COM7, COM8, COM9, LPT1, LPT2, LPT3, LPT4, LPT5, LPT6, LPT7, LPT8, and LPT9. As noticed by slowdog, it is mentioned in the same MSDN document as above that \\.\CON is the correct way to access such a device name directly.
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