A clean way to store a function and its (arbitrary-type, arbitrary-number) arguments

Question

For a library, I'd like a function to accept another function and its arguments, then store them all for calling later. The arguments must allow for any mixture of types, but the functions only need to return void. Something like this:

void myFunc1(int arg1, float arg2);
void myFunc2(const char *arg1);
class DelayedCaller
{ ...
public:
    static DelayedCaller *setup(Function func, …);
};

...
DelayedCaller* caller1 = DelayedCaller::setup(&myFunc1, 123, 45.6);
DelayedCaller* caller2 = DelayedCaller::setup(&myFunc2, "A string");

caller1->call(); // Calls myFunc1(), with arguments 123 and 45.6
caller2->call(); // Calls myFunc2(), with argument "A string"

One approach is to make DelayedCaller::setup() accept a std::function, and have my library users use std::bind() prior to calling setup(). However, is there a way to implement setup() such that users don't need to do the binding themselves?

Edit: DelayedCaller is an existing class. setup() is a new static method I'd like to add.

Answer 1

An possibility is to use variadic templates and call std::bind() from within the setup() function:

#include <iostream>
#include <string>
#include <functional>
#include <memory>

void myFunc1(int arg1, float arg2)
{
    std::cout << arg1 << ", " << arg2 << '\n';
}
void myFunc2(const char *arg1)
{
    std::cout << arg1 << '\n';
}

class DelayedCaller
{
public:
    template <typename TFunction, typename... TArgs>
    static std::unique_ptr<DelayedCaller> setup(TFunction&& a_func,
                                                TArgs&&... a_args)
    {
        return std::unique_ptr<DelayedCaller>(new DelayedCaller(
            std::bind(std::forward<TFunction>(a_func),
                      std::forward<TArgs>(a_args)...)));
    }
    void call() const { func_(); }

private:
    using func_type = std::function<void()>;
    DelayedCaller(func_type&& a_ft) : func_(std::forward<func_type>(a_ft)) {}
    func_type func_;
};

int main()
{
    auto caller1(DelayedCaller::setup(&myFunc1, 123, 45.6));
    auto caller2(DelayedCaller::setup(&myFunc2, "A string"));

    caller1->call();
    caller2->call();

    return 0;
}

Output:

123, 45.6
A string

Return a smart pointer, such as std::unique_ptr, instead of returning a raw pointer (or return by value and avoid dynamic allocation. The func_type is moveable if the arguments are moveable, or it may be quite cheap to copy anyway. You may need to define the move constructor and move assignment operator, they are generated under certain conditions).

Answer 2

You could use lambda functions to hide the bindings:

#include <functional>

class DelayedCaller : public std::function< void(void) > {
public:
    DelayedCaller(std::function< void(void) > fn)
      : std::function< void(void) >(fn) {}
};

DelayedCaller caller1([]() { myFunc1(123, 45.6); });
DelayedCaller caller2([]() { myFunc2("A string"); });

caller1(); // Calls myFunc1(), with arguments 123 and 45.6
caller2(); // Calls myFunc2(), with argument "A string"

This also gives your library's users more flexibility. They're not limited to a single function call and the functions have access to the original environment they were created in:

int x;

DelayedCaller caller3 = [&x]() {
    if (x == 0)
        DoSomething();
    else
        DoSomethingElse();
};