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This seems horrible inefficient. Can someone give me a better Ruby way.
def round_value x = (self.value*10).round/10.0 # rounds to two decimal places r = x.modulo(x.floor) # finds remainder f = x.floor self.value = case when r.between?(0, 0.25) f when r.between?(0.26, 0.75) f+0.5 when r.between?(0.76, 0.99) f+1.0 end end 
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The round() method can be used to round a number to a specified number of decimal places in Ruby. We can use it without a parameter ( round() ) or with a parameter ( round(n) ). n here means the number of decimal places to round it to.
Ruby | Numeric round() function The round() is an inbuilt method in Ruby returns a number rounded to a number nearest to the given number with a precision of the given number of digits after the decimal point. In case the number of digits is not given, the default value is taken to be zero.
Ruby Float round() method with exampleround() is a float class method which return a float value rounded to the nearest value with n digits decimal digits precision.
Ruby Language Numbers Rounding Numbers The round method will round a number up if the first digit after its decimal place is 5 or higher and round down if that digit is 4 or lower.
class Float def round_point5 (self * 2).round / 2.0 end end A classic problem: this means you're doing integer rounding with a different radix. You can replace '2' with any other number.
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