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%2F in URL breaks and does not reference to the .php file required [duplicate]

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I need to pass / as a variable as part of a URL.

My structure looks like this: www.domain.com/listings/page-1/city-Burnaby+South/type-Townhome/bedroom-2/bathroom-2

In this case, it ultimately boils down to listings.php and everything else beyond it becomes parameters taht my PHP script parses through using the $_SERVER['REQUEST_URI'] var.

However when one of hte variables becomes "Apartment/Condo" and the / becomes %2F via urlencode() in PHP when the URL is generated, the whole thing chokes and I get a "Not Found" error.

How do I pass the / without breaking the URL? What am I missing? I thought the whole point of these urlencode() characters (%2F, %20 etc.) were there to escape these issues.

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jeffkee Avatar asked Feb 09 '12 07:02

jeffkee


1 Answers

Urls with %2f / or %5c \ return a 404 from Apache for security purposes.

You may modify Apache config to enable AllowEncodedSlashes On or NoDecode. Keep in mind that this may introduce unintended security issues, which this "feature" is designed to mitigate.

Apache docs: http://httpd.apache.org/docs/current/mod/core.html#allowencodedslashes

Solved:

  • Receive an HTTP 400 error if %2F is part of the GET URL in JBOSS

This one got me too -- thanks for the question

like image 58
here Avatar answered Sep 21 '22 03:09

here