I had to write a routine that increments the value of a variable by 1 if its type is number
and assigns 0 to the variable if not, where the variable is initially null
or undefined
.
The first implementation was v >= 0 ? v += 1 : v = 0
because I thought anything not a number would make an arithmetic expression false, but it was wrong since null >= 0
is evaluated to true. Then I learned null
behaves like 0 and the following expressions are all evaluated to true.
null >= 0 && null <= 0
!(null < 0 || null > 0)
null + 1 === 1
1 / null === Infinity
Math.pow(42, null) === 1
Of course, null
is not 0. null == 0
is evaluated to false. This makes the seemingly tautological expression (v >= 0 && v <= 0) === (v == 0)
false.
Why is null
like 0, although it is not actually 0?
Your real question seem to be:
Why:
null >= 0; // true
But:
null == 0; // false
What really happens is that the Greater-than-or-equal Operator (>=
), performs type coercion (ToPrimitive
), with a hint type of Number
, actually all the relational operators have this behavior.
null
is treated in a special way by the Equals Operator (==
). In a brief, it only coerces to undefined
:
null == null; // true
null == undefined; // true
Value such as false
, ''
, '0'
, and []
are subject to numeric type coercion, all of them coerce to zero.
You can see the inner details of this process in the The Abstract Equality Comparison Algorithm and The Abstract Relational Comparison Algorithm.
In Summary:
Relational Comparison: if both values are not type String, ToNumber
is called on both. This is the same as adding a +
in front, which for null coerces to 0
.
Equality Comparison: only calls ToNumber
on Strings, Numbers, and Booleans.
I'd like to extend the question to further improve visibility of the problem:
null >= 0; //true
null <= 0; //true
null == 0; //false
null > 0; //false
null < 0; //false
It just makes no sense. Like human languages, these things need be learned by heart.
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