What require('./.'); means?

Question

Found this strange looking URL which is working by the way.

var _ = require('./.');

Can someone explain what this will do in reality and why they are doing it ?

Answer 1

It may be a typo, but it is normalized to ..

If you're ever curious about how a path is resolved in Node.js, you can use path methods and require.resolve to see what is going on.

> path.normalize('./.')
'.'
> path.normalize('././././././././.')
'.'
> require.resolve('./.') // assuming `index.js` exists...
'/path/to/index.js'