I want to substitute variables in a string like console.log does.
What I want to achieve is something like this:
let str = 'My %s is %s.';
replaceStr(string, /* args */) {
// I need help with defining this function
};
let newStr = replaceStr(str, 'name', 'Jackie');
console.log(newStr);
// output => My name is Jackie.
/*
This is similar to how console.log does:
// console.log('I\'m %s.', 'Jack');
// => I'm Jack.
*/
I am not able to figure out how to do that. Any help will be much appreciated.
Thank you.
You could prototype it to the String object. Something like this:
String.prototype.sprintf = function() {
var counter = 0;
var args = arguments;
return this.replace(/%s/g, function() {
return args[counter++];
});
};
let str = 'My %s is %s.';
str = str.sprintf('name', 'Alex');
console.log(str); // 'My name is Alex'
You can use spread operator (ES6):
function replaceStr(string, ...placeholders) {
while (placeholders.length > 0) {
string = string.replace('%s', placeholders.shift());
}
return string;
}
EDIT: Based on lexith's answer, we can avoid the explicit loop:
function replaceStr(string, ...placeholders) {
var count = 0;
return string.replace(/%s/g, () => placeholders[count++]);
}
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