Here's a basic regex technique that I've never managed to remember. Let's say I'm using a fairly generic regex implementation (e.g., grep or grep -E). If I were to do a list of files and match any that end in either .sty or .cls, how would I do that?
ls | grep -E "\.(sty|cls)$"
\. matches literally a "." - an unescaped . matches any character(sty|cls) - match "sty" or "cls" - the | is an or and the brackets limit the expression.$ forces the match to be at the end of the lineNote, you want grep -E or egrep, not grep -e as that's a different option for lists of patterns.
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