RSpec: How could I use the array include matcher in the expect syntax

Question

I use new RSpec syntax (expect instead of should) and I'd like to test if an array includes elements of another array. In the old syntax it would be:

array1.should include(array2)

In the new syntax I tried to write:

expect(array1).to include(array2)

but I got an error (that's quite reasonable):

TypeError: wrong argument type Array (expected Module)

Then I wrote:

expect(array1).to be_include(array2)

but it's ugly and it didn't work: apparently it checks if array2 is element of array1 not if all elements of array2 are included in array1.

Finally I wrote:

expect(array1 & array2).to eq(array2)

but it's not the prettiest solution. Do you know any better?

Answer 1

You need to splat the arguments when passing them to the array matcher:

expect(array1).to include(*array2)

This is because you usually list out literals, e.g.:

expect([1, 2, 3]).to include(1, 2)

That said, expect(array1).to include(array2) should not fail with a weird error like you got, and in fact it works and passes in an example like:

  it 'includes a sub array' do
    array2 = ["a"]
    array1 = [array2]
    expect(array1).to include(array2)
  end

Answer 2

Try this one:

expect(array1).to include *array2

Answer 3

To test if one array is subset of another array its perhapse good idea to introduce set. And then you can write it like this... (Solution uses Set#subset?)

require "set"

describe "Small test" do
  let(:array1) { %w{a b c d} }
  let(:array2) { %w{b c} }

  let(:array1_as_set) { array1.to_set }
  let(:array2_as_set) { array2.to_set }

  subject { array2_as_set }

  context "inclusion of w/ \"expect\"" do
    it { expect(subject).to be_subset(array1_as_set) }
  end

  context "inclusion of w/ \"should\"" do
    it { should be_subset(array1_as_set) }
  end

end