ZSH for loop array variable issue

Question

I'm working in zsh, but I'm sure that bash instructions will also be helpful.

I need to have a for loop that goes through the values stored in the array lw and then launches a shell script, based on the name value stored in the array.

So far, this is what I've come up with:

$lw=('plugin1' 'plugin2' 'plugin3')  for i in $lw;   do . ~/Library/Rogall/plugins/$lw[$i]/lw.prg end; done 

Running this gives me an error saying that it can't find ~/Library/Rogall/plugins//lw.prg. It appears as if it's ignoring my variable all together.

Any ideas where I've messed up?

Answer 1

It's actually much simpler than that:

lw=('plugin1' 'plugin2' 'plugin3')  for i in $lw; do   . ~/Library/Rogall/plugins/$i/lw.prg end done 

In summary:

• Assign to foo, not $foo (the shell would try to expand $foo and assign to whatever it expands to; typically not useful)
• Use the loop variable directly; it contains the array value rather than the index