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Made a xslt template with output instruction for <DOCTYPE>:
<xsl:output media-type="text/html" method="html" encoding="windows-1251" doctype-public="-//W3C//DTD XHTML 1.1//EN" doctype-system="http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd" omit-xml-declaration="yes"/>
In xsl-debug I'm receiving right
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd">
on top of the html.
But when I'm using XslCompiledTransform etc.. output starts from
<html xmlns="http://www.w3.org/1999/xhtml">
So, DOCTYPE is missed. Why? Right properties of XslCompiledTransform initialized just like I set in <xsl:output> .
Code:
using (var sw = new StringWriter())
{
XslCompiledTransform xslt = new XslCompiledTransform();
XmlEmbeddedResourceResolver resolver = new XmlEmbeddedResourceResolver();
xslt.Load("clires://DLLPATH/xsl/blank.xsl", XsltSettings.TrustedXslt, resolver);
XmlWriterSettings set = new XmlWriterSettings();
set.ConformanceLevel = ConformanceLevel.Auto;
xslt.Transform(ticket, XmlWriter.Create(sw, set));
return sw.ToString();
}
How can I get DOCTYPE from XslCompiledTransform?
272
You need to use the XmlWriterSettings from the OutputSettings property in XslCompiledTransform
XmlWriterSettings set = xslt.OutputSettings;
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