Wrong interface method called [duplicate]

Question

If I have a generic interface with a covariant type parameter, like this:

interface IGeneric<out T>
{
    string GetName();
}

And If I define this class hierarchy:

class Base {}
class Derived1 : Base{}
class Derived2 : Base{}

Then I can implement the interface twice on a single class, like this, using explicit interface implementation:

class DoubleDown: IGeneric<Derived1>, IGeneric<Derived2>
{
   string IGeneric<Derived1>.GetName()
   {
     return "Derived1";
   }

   string IGeneric<Derived2>.GetName()
   {
     return "Derived2";
   }  
}

If I use the (non-generic)DoubleDown class and cast it to IGeneric<Derived1> or IGeneric<Derived2> it functions as expected:

var x = new DoubleDown();
IGeneric<Derived1> id1 = x;        //cast to IGeneric<Derived1>
Console.WriteLine(id1.GetName());  //Derived1
IGeneric<Derived2> id2 = x;        //cast to IGeneric<Derived2>
Console.WriteLine(id2.GetName());  //Derived2

However, casting the x to IGeneric<Base>, gives the following result:

IGeneric<Base> b = x;
Console.WriteLine(b.GetName());   //Derived1

I expected the compiler to issue an error, as the call is ambiguous between the two implementations, but it returned the first declared interface.

Why is this allowed?

(inspired by A class implementing two different IObservables?. I tried to show to a colleague that this will fail, but somehow, it didn't)

Answer 1

If you have tested both of:

class DoubleDown: IGeneric<Derived1>, IGeneric<Derived2> {
    string IGeneric<Derived1>.GetName() {
        return "Derived1";
    }

    string IGeneric<Derived2>.GetName() {
        return "Derived2";
    }
}

class DoubleDown: IGeneric<Derived2>, IGeneric<Derived1> {
    string IGeneric<Derived1>.GetName() {
        return "Derived1";
    }

    string IGeneric<Derived2>.GetName() {
        return "Derived2";
    }
}

You must have realized that the results in reality, changes with the order you declaring the interfaces to implement. But I'd say it is just unspecified.

First off, the specification(§13.4.4 Interface mapping) says:

• If more than one member matches, it is unspecified which member is the implementation of I.M.
• This situation can only occur if S is a constructed type where the two members as declared in the generic type have different signatures, but the type arguments make their signatures identical.

Here we have two questions to consider:

• Q1: Do your generic interfaces have different signatures?
  A1: Yes. They are IGeneric<Derived2> and IGeneric<Derived1>.

• Q2: Could the statement IGeneric<Base> b=x; make their signatures identical with type arguments?
  A2: No. You invoked the method through a generic covariant interface definition.

Thus your call meets the unspecified condition. But how could this happen?

Remember, whatever the interface you specified to refer the object of type DoubleDown, it is always a DoubleDown. That is, it always has these two GetName method. The interface you specify to refer it, in fact, performs contract selection.

The following is the part of captured image from the real test

This image shows what would be returned with GetMembers at runtime. In all cases you refer it, IGeneric<Derived1>, IGeneric<Derived2> or IGeneric<Base>, are nothing different. The following two image shows more details:

As the images shown, these two generic derived interfaces have neither the same name nor another signatures/tokens make them identical.