#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
int main(int argc, char *argv[])
{
size_t sz = atol(argv[1]);
char *arr = malloc(sz);
sleep(10);
}
I compiled this code and tried to run it, used pmap to see the memory mapping of the program.
When I use some big number like 1024000, I get a mapping like this:
3901: ./alloc_program 1024000
0000560192f43000 4K r---- alloc_program
0000560192f44000 4K r-x-- alloc_program
0000560192f45000 4K r---- alloc_program
0000560192f46000 4K r---- alloc_program
0000560192f47000 4K rw--- alloc_program
0000560192fac000 132K rw--- [ anon ]
00007f75b69e9000 1004K rw--- [ anon ] <---- I believe this is the allocated memory
00007f75b6ae4000 148K r---- libc-2.31.so
00007f75b6b09000 1504K r-x-- libc-2.31.so
00007f75b6c81000 296K r---- libc-2.31.so
00007f75b6ccb000 4K ----- libc-2.31.so
00007f75b6ccc000 12K r---- libc-2.31.so
00007f75b6ccf000 12K rw--- libc-2.31.so
00007f75b6cd2000 24K rw--- [ anon ]
00007f75b6ce7000 4K r---- ld-2.31.so
00007f75b6ce8000 140K r-x-- ld-2.31.so
00007f75b6d0b000 32K r---- ld-2.31.so
00007f75b6d14000 4K r---- ld-2.31.so
00007f75b6d15000 4K rw--- ld-2.31.so
00007f75b6d16000 4K rw--- [ anon ]
00007ffe2b26e000 132K rw--- [ stack ]
00007ffe2b318000 12K r---- [ anon ]
00007ffe2b31b000 4K r-x-- [ anon ]
ffffffffff600000 4K --x-- [ anon ]
total 3496K
I suppose that the marked line is the memory allocated by malloc (maybe I'm wrong).
But when I use some small number like 10240, I don't see that anything is allocated:
3879: ./alloc_program 10240
000055e428e26000 4K r---- alloc_program
000055e428e27000 4K r-x-- alloc_program
000055e428e28000 4K r---- alloc_program
000055e428e29000 4K r---- alloc_program
000055e428e2a000 4K rw--- alloc_program
000055e42a257000 132K rw--- [ anon ]
00007f102332c000 148K r---- libc-2.31.so
00007f1023351000 1504K r-x-- libc-2.31.so
00007f10234c9000 296K r---- libc-2.31.so
00007f1023513000 4K ----- libc-2.31.so
00007f1023514000 12K r---- libc-2.31.so
00007f1023517000 12K rw--- libc-2.31.so
00007f102351a000 24K rw--- [ anon ]
00007f102352f000 4K r---- ld-2.31.so
00007f1023530000 140K r-x-- ld-2.31.so
00007f1023553000 32K r---- ld-2.31.so
00007f102355c000 4K r---- ld-2.31.so
00007f102355d000 4K rw--- ld-2.31.so
00007f102355e000 4K rw--- [ anon ]
00007fff1d513000 132K rw--- [ stack ]
00007fff1d570000 12K r---- [ anon ]
00007fff1d573000 4K r-x-- [ anon ]
ffffffffff600000 4K --x-- [ anon ]
total 2492K
1 - Why it doesn't allocate when the memory size is relatively small?
2 - Why the allocated memory size is not exactly the same? In the first run, it shows that the size is 1004KB while I've only allocated 1000KB.
1 - Why it doesn't allocate when the memory size is relatively small?
The task of the function malloc is to provide the application with memory, whenever it asks for it. Theoretically, malloc could, as you suggest, just forward all requests for memory allocations to the operating system's kernel, so that it only acts as a wrapper for the kernel's memory allocator. However, this has the following disadvantages:
For these reasons, it is more efficient for malloc to not forward memory allocation requests directly to the kernel, but to rather act as an intermediary between the application's memory allocation requests and the kernel. It requests memory in larger amounts from the kernel, so that it can satisfy many smaller memory allocation requests from the application.
Therefore, only when asking for a large amount of memory at once, will malloc forward that memory allocation request to the kernel.
2 - Why the allocated memory size is not exactly the same? In the first run, it shows that the size is
1004KBwhile I've only allocated1000KB.
The malloc allocator must keep track of all the memory allocations it granted to the application and also keep track of all the memory allocations that it has been granted by the kernel. To store this information, it requires a bit of addititional memory space. This additional space is called "overhead".
What you're seeing in the pmap output is almost certainly the addition needed to the malloc arena to satisfy larger requests, not any single request.
The arena is the pool of memory from which allocations are handed out and there's a good chance this starts at a certain size and is only expanded on demand.
For example, if the initial arena is 1000K, any allocation that does not exhaust that will have no need to get extra arena space. If you do exhaust that space, the process will try to request more arena from the underlying environment so it can satisfy the extra demand.
As to why the size isn't what you requested, there are (at least) two possible reasons. First, the arena isn't just the memory allocated for your purposes, it also holds control information so that the memory can be properly managed (sizes, checksums, pointers, free list and so on).
Secondly, malloc may over-allocate on the expectation that this won't be the last request that exhausts the current arena. Some memory allocation strategies go so far as to double the current arena size when requesting more, in order to amortise the cost of doing so.
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