Why doesn't a pointer to an element in a c-string return just the element?

Question

I'm trying to understand how pointers work here. The findTheChar function searches through str for the character chr. If the chr is found, it returns a pointer into str where the character was first found, otherwise nullptr (not found). My question is why does the function print out "llo" instead of "l"? while the code I wrote in main return an "e" instead of "ello"?

#include <iostream>
using namespace std;

const char* findTheChar(const char* str, char chr)
{
    while (*str != 0)
    {
        if (*str == chr)
            return str;
        str++;
    }
    return nullptr;
}

int main()
{
    char x[6] = "hello";
    char* ptr = x;
    while (*ptr != 0)
    {
        if (*ptr == x[1])
            cout << *ptr << endl; //returns e
            ptr++;
    }
    cout << findTheChar("hello", 'l') << endl; // returns llo
}

Answer 1

A C-string is a character buffer that is terminated by a '\0' character. Passing them around involves just passing a pointer to the first element.

All the library routines know that they may read characters starting at the address they are given, until they reach '\0'. Since that's how operator<< for std::cout is designed, it assumes you pass it the starting address of a C-string. That's the contract.

If you want to print a single character, you'll need to dereference that pointer.