In my application I need to conduct an IP lookup as a prerequisite to proceeding with execution of another function that needs that data. Originally, I called the function as follows:
$(document).ready(function(){
var ipUrl = "myURL?callback=?";
$.getJSON(ipUrl, function(data) {
window.ip = data['ip'];
console.log("inside function" + window.ip);
}).done(printIp());
});
function printIp() {
console.log("function is done " + window.ip);
}
However, this outputs as
function is done undefined
inside function <ip_address>
I.e. the printIp() function is called before the $.getJSON is actually complete.
If however, I wrap the printIp() call within an anonymous function as follows:
$.getJSON(ipUrl, function(data) {
window.ip = data['ip'];
console.log("inside function" + window.ip);
}).done(function() {
printIp();
});
I get:
inside function <ip_address>
function is done <ip_address>
As I would expect. What is going on here? Why do I need to wrap the function call in an anonymous function?
your code says
}).done(printIp());
what this does is calling printIp and using the result of the function call as an argument to the done method.
what you actually want is passing the function as a done handler. use }).done(printIp); to do this instead.
You are executing printIp right away. Try it without the ():
$.getJSON(ipUrl, function(data) {
window.ip = data['ip'];
console.log("inside function" + window.ip);
}).done(printIp);
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