I would like to be able to obtain references (both immutable and mutable) to the usize wrapped in Bar in the Foo enum:
use Foo::*;
#[derive(Debug, PartialEq, Clone)]
pub enum Foo {
Bar(usize)
}
impl Foo {
/* this works */
fn get_bar_ref(&self) -> &usize {
match *self {
Bar(ref n) => &n
}
}
/* this doesn't */
fn get_bar_ref_mut(&mut self) -> &mut usize {
match *self {
Bar(ref mut n) => &mut n
}
}
}
But I can't obtain the mutable reference because:
ndoes not live long enough
I was able to provide both variants of similar functions accessing other contents of Foo that are Boxed - why does the mutable borrow (and why only it) fail with an unboxed primitive?
These examples show the sample problem:
fn implicit_reborrow<T>(x: &mut T) -> &mut T {
x
}
fn explicit_reborrow<T>(x: &mut T) -> &mut T {
&mut *x
}
fn implicit_reborrow_bad<T>(x: &mut T) -> &mut T {
&mut x
}
fn explicit_reborrow_bad<T>(x: &mut T) -> &mut T {
&mut **&mut x
}
The explicit_ versions show what the compiler deduces through deref coercions.
The _bad versions both error in the exact same way, while the other two compile.
This is either a bug, or a limitation in how lifetimes are currently implemented in the compiler. The invariance of &mut T over T might have something to do with it, because it results in &mut &'a mut T being invariant over 'a and thus more restrictive during inference than the shared reference (&&'a T) case, even though in this situation the strictness is unnecessary.
You need to replace Bar(ref mut n) => &mut n with Bar(ref mut n) => n.
When you use ref mut n in Bar(ref mut n), it creates a mutable
reference to the data in Bar, so the type of n is &mut usize.
Then you try to return &mut n of &mut &mut u32 type.
This part is most likely incorrect.
Now deref coercion kicks in and converts
&mut ninto&mut *n, creating a temporary value*nof typeusize, which doesn't live long enough.
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