Visiting every value in a multi dimensional array

Question

I am trying to build a function to visit every value in a multi-dimensional array that has no limit to dimensions.

The depth of each value is generated.

var array = [[0, [[1, [2, [3, []]]],[4, []],[5, [6, []]],[7, [8, [9, []]]],[10, []]]]];

function visitall(a) {
  for (i = 0; i < (a.length); i++) {
      console.log(a[i][0])
      for (j = 0; j < (a[i][1].length); j++) {
          console.log(a[i][1][j][0])
          for (n = 0; n < (a[i][1][j][1].length); n++) {
              console.log(a[i][1][j][1][n][0])
          }
      }
  }
}

visitall(array)

Answer 1

You can use recursion.

Use Array.isArray to check if variable is array. If it is, do a forEach and call the visitall function again.

function visitall(a) {
  if (Array.isArray(a)) a.forEach(visitall);
  else console.log(a); //Not an array, so console.log
}


var array = [[0, [[1, [2, [3, []]]],[4, []],[5, [6, []]],[7, [8, [9, []]]],[10, []]]]];

visitall(array);

---

Or you can join, split and filter so you can get all the number in the array. You can now loop as normal.

var array = [[0, [[1, [2, [3, []]]],[4, []],[5, [6, []]],[7, [8, [9, []]]],[10, []]]]];

var result = array.join().split(',').filter(o => o !== '');

console.log(result);

Answer 2

just use recursion

var array = [
  [0, [[1, [2, [3, []]]], [4, []], [5, [6, []]], [7, [8, [9, []]]], [10, []]]]
];

function visit(a) {
  if (Array.isArray(a)) {
    for (let i = 0; i < a.length; i++) visit(a[i]);
  } else {
    console.log(a);
  }
}

visit(array);