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Vectorize loop with repeating indices

I have a vector of indices that contains repeating values:

 IN <- c(1, 1, 2, 2, 3, 4, 5)     

I would like to uses these indices to subtract two vectors:

ST <- c(0, 0, 0, 0, 0, 0, 0)
SB <- c(1, 1, 1, 1, 1, 1, 1)

However, I would like to do the subtraction in "order" such that after subtraction of the first index values (0, 1), the second substraction would "build off" the first subtraction. I would like to end up with a vector FN that looks like this:

c(-2, -2, -1, -1, -1, 0, 0)

This is easy enough to do in a for loop:

for(i in seq_along(IN)){
  ST[IN[i]] <- ST[IN[i]] - SB[IN[i]]
}

But I need to run this loop many times on long vectors and this can take many hours. Is there any way to vectorize this task and avoid a for loop? Maybe using a data.table technique?

like image 215
ken Avatar asked Jul 26 '26 02:07

ken


2 Answers

Sure, with data.table, it's

library(data.table)
DT = data.table(ST)
mDT = data.table(IN, SB)[, .(sub = sum(SB)), by=.(w = IN)]
DT[mDT$w, ST := ST - mDT$sub ]

   ST
1: -2
2: -2
3: -1
4: -1
5: -1
6:  0
7:  0

Or with base R:

w = sort(unique(IN))
ST[w] <- ST[w] - tapply(SB, IN, FUN = sum)
# [1] -2 -2 -1 -1 -1  0  0
like image 188
Frank Avatar answered Jul 28 '26 16:07

Frank


Here is an option using aggregate in base R:

ag <- aggregate(.~IN, data.frame(IN, ST[IN]-SB[IN]), sum)
replace(ST, ag[,1], ag[,2])

#[1] -2 -2 -1 -1 -1  0  0

OR using xtabs:

d <- as.data.frame(xtabs(B~A, data.frame(A=IN, B=ST[IN]-SB[IN])))
replace(ST, d[,1], d[,2])
like image 27
989 Avatar answered Jul 28 '26 16:07

989