Variable info in included PHP file

Question

Currently I'm using a PHP file wih the footer of my website so I can just include it on every page and change just one file to change the footer on every page of the site.

Now, I would like to do the same with the menu on my site which is like this:

<ul>
<li><a href="#">Menu 1</a></li>
<li><a href="#" class="active">Menu 2</a></li>
<li><a href="#">Menu 3</a></li>
<li><a href="#">Menu 4</a></li>
</ul>

The class active highlights the name of the page the user is on, so if the user is at the 'Menu 2' page of the website the li 'Menu 2' is highlighted. Now I wonder how I can put this menu in a seperate file, like 'menu.php' which I can include in every page, but still be able to change the class="active" to the page the user is at.

Answer 1

$open_page = substr($_SERVER["SCRIPT_NAME"], strrpos($_SERVER["SCRIPT_NAME"],"/")+1);

and

<ul>
<li><a href="#" <?php if($open_page == "Menu_1.php") echo " class= 'active' "; ?>>Menu 1</a></li>
<li><a href="#" <?php if($open_page == "Menu_2.php") echo " class= 'active' "; ?>>Menu 2</a></li>
<li><a href="#" <?php if($open_page == "Menu_3.php") echo " class= 'active' "; ?>>Menu 3</a></li>
<li><a href="#" <?php if($open_page == "Menu_4.php") echo " class= 'active' "; ?>>Menu 4</a></li>
</ul>

Answer 2

Comparing with file-name is not the best-practice & when your project gets heavy, its tough to maintain

Call the footer from page & pass a page identifier-

------ Menu1_page.php --------    
<?php
    require_once 'footer.php';
    getFooter('Menu1');
?>

in footer.php, keep the footer within a function

---- footer.php -----
<?php
function getFooter($activeid){
   ?>
      <ul>
      <li><a href="#" class="<?=($activeid=='Menu1')?'active':''?>">Menu 1</a></li>
      <li><a href="#" class="<?=($activeid=='Menu2')?'active':''?>">Menu 2</a></li>
        ......
      </ul>
   <?php
}
?>