I am trying to write a program in java which can count number of '1' in a range of numbers.
For examples: if we look from range 1 - 20 we will get 12 1's
1, 2,3....9, 1 0, 1 1 .... 1 9, 20.
here is the code i have written.
public class Count_no_of_ones
{
public static void main( String args[] )
{
int count = 0;
for ( int i = 1; i<=20; i++ )
{
int a=i;
char b[] = a.toString().toCharArray(); //converting a number to single digit array
for ( int j = 0; j < b.length; j++ )
{
if( Integer.parseInt(b[j]) == 1 )
{
count++; // checking and counting if the element in array is 1 or not.
}
}
}
System.out.println("number of ones is : " + count);
}
}
I am getting two errors on compiling.
D:\Programs\Java>javac Count_no_of_ones.java
Count_no_of_ones.java:10: error: int cannot be dereferenced
char b[] = a.toString().toCharArray(); //converting a number to single digit array
^
Count_no_of_ones.java:14: error: no suitable method found for parseInt(char)
if( Integer.parseInt(b[j]) == 1 )
^
method Integer.parseInt(String) is not applicable
(actual argument char cannot be converted to String by method invocation conversion)
method Integer.parseInt(String,int) is not applicable
(actual and formal argument lists differ in length)
2 errors
D:\Programs\Java>
Can you also explain what i did wrong in the code. i never had problem with Integer.parseInt and this de-referencing problem is new to me. i just heard about it in awt class but i never actually faced it.
You can't call methods on primitive types in Java. Use the static method Integer.toString instead:
char b[] = Integer.toString(a).toCharArray();
You also don't actually need to convert to a character array. You can index into a string using charAt.
The method parseInt accepts a string, not a char, so this line doesn't work:
if( Integer.parseInt(b[j]) == 1 )
Instead do the comparison with the char '1':
if (b[j] == '1')
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