Using out parameter in a function that has a return value

Question

I have a function such as this one:

public string MyFunction(int a, out int b)
{
   var test = ""
   b = 6;
   return test;
}

and then on the receiving end:

int b = 0;
var testOutcome = MyFunction(3, b);

I wonder how to get the value of: b in this scenario?

something like:

var bOutcome = ....; 

Answer 1

You get the out parameter from the method. Note that you also need to add the out keyword in the parameter signature of the method:

int b = 0;  // initialization is redundant
string  testOutcome = MyFunction(3, out b);
// b is initialized now

Although variables passed as out arguments do not have to be initialized before being passed, the called method is required to assign a value before the method returns.