The new Java 8 stream framework and friends make for some very concise Java code, but I have come across a seemingly-simple situation that is tricky to do concisely.
Consider a List<Thing> things and method Optional<Other> resolve(Thing thing). I want to map the Things to Optional<Other>s and get the first Other.
The obvious solution would be to use things.stream().flatMap(this::resolve).findFirst(), but flatMap requires that you return a stream, and Optional doesn't have a stream() method (or is it a Collection or provide a method to convert it to or view it as a Collection).
The best I can come up with is this:
things.stream()
.map(this::resolve)
.filter(Optional::isPresent)
.map(Optional::get)
.findFirst();
But that seems awfully long-winded for what seems like a very common case.
Anyone have a better idea?
Optional.stream has been added to JDK 9. This enables you to do the following, without the need of any helper method:
Optional<Other> result =
things.stream()
.map(this::resolve)
.flatMap(Optional::stream)
.findFirst();
Yes, this was a small hole in the API, in that it's somewhat inconvenient to turn an Optional<T> into a zero-or-one length Stream<T>. You could do this:
Optional<Other> result =
things.stream()
.map(this::resolve)
.flatMap(o -> o.isPresent() ? Stream.of(o.get()) : Stream.empty())
.findFirst();
Having the ternary operator inside the flatMap is a bit cumbersome, though, so it might be better to write a little helper function to do this:
/**
* Turns an Optional<T> into a Stream<T> of length zero or one depending upon
* whether a value is present.
*/
static <T> Stream<T> streamopt(Optional<T> opt) {
if (opt.isPresent())
return Stream.of(opt.get());
else
return Stream.empty();
}
Optional<Other> result =
things.stream()
.flatMap(t -> streamopt(resolve(t)))
.findFirst();
Here, I've inlined the call to resolve() instead of having a separate map() operation, but this is a matter of taste.
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