Typescript + jQuery Promises = .then Type mismatch

Question

i'm using Typescript and jQuery Promises and I am experiencing an error with the following code:

    var promiseOne = this.myFunc(1);
    var promiseTwo = this.myFunc(2);

    $.when(promiseOne, promiseTwo).then((valFromPromiseOne: number, valFromPromiseTwo: number) =>   //Error here (see below)
    {
        //Use both return values of the promises...
    });

    myFunc(value: number): JQueryPromise<number>
    {
        var dfd = $.Deferred();

        setTimeout(function ()
        {
            dfd.resolve(value);
        }, 1000);

        return dfd.promise();
    }

The error I'm getting is:

    Error   5   Supplied parameters do not match any signature of call target:
        Call signatures of types '(valFromPromiseOne: number, valFromPromiseTwo: number) => void' and '(value: any) => {}' are incompatible:
            Call signature expects 1 or fewer parameters.

I want the function to execute only when both Promises are resolved.

Am I doing somenthing wrong? Is there a different way to achieve what I want?

Thanks

Answer 1

Finally found out the way to do it. The second parameter has to be optional.

$.when(promiseOne, promiseTwo).then((valFromPromiseOne: number, valFromPromiseTwo?: number) =>   //valFromPromiseTwo has to be optional
{
    //Use both return values of the promises...
});

After this change, it is working fine.

Not sure if it is the right way. But it worked for me.