type casting int to double java?

Question

I'm practicing debugging and there is a question that i'm unsure on, it's asking what is wrong and what can I do to fix it I read the book chapter on it but not specific enough. pasted from the book:

int a = 26.4 ^ When you compile, this is the message:

Test.Java:8: possible loss of precision int a = 26.4;

required: int found : double 1 error

I have a decent understanding on why there is an error, because of how double has a higher precedence than int and how an int cant necessarily store a double value.

My question is, is there a way to type cast variable a into a double type? Or is the only way to fix this by changing a from int to double?

thanks

Answer 1

The only possibilities you have are:

• Type cast the double into an int if you want to store your number as an integer:

  int a = (int)26.4   // so a will be 26
  

  (you will obviously lose precision this way)

• Store the number as a double to keep the precision:

  double a = 26.4
  

Answer 2

Casting will not help at anything, look at the code below:

//int a = 26.4; // gives compile error
int a = (int) 26.4; // gives 26
double b = a; // gives 26.0
double c = (double) a; // also gives 26.0