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Templated functions in templated classes

I am constructing a library that makes use of expression templates, where I make heavily use of templated functions in classes. All my code is running and recently I decided to make the main class templated to allow for using it on data of different kinds. However, I can no longer specialize my functions. How do I solve this? I have attached a small test program that shows the problem.

My previous Animal class was not templated and then this code works fine.

#include<iostream>
#include<vector>

// Example templated class with templated function
template<class T>
class Animals
{
  public:
    template<class X>
    void printFood(const X& x) const { std::cout << "We eat " << x << "!" << std::endl; }

  private:
    std::vector<T> animals;
};

// How do I specialize?
template<class T> template<>
void Animals<T>::printFood(const unsigned int& x) const { std::cout << "We don't want to eat " << x << "!" << std::endl; }

// Main loop;
int main()
{
  Animals<double> doubleAnimals;

  const int banana = 42;
  doubleAnimals.printFood(banana);

  const unsigned int apple = 666;
  doubleAnimals.printFood(apple);

  return 0;
}
like image 345
Chiel Avatar asked Feb 05 '26 20:02

Chiel


1 Answers

This simply isn't possible

[temp.expl.spec]

16 In an explicit specialization declaration for a member of a class template or a member template that appears in namespace scope, the member template and some of its enclosing class templates may remain unspecialized, except that the declaration shall not explicitly specialize a class member template if its enclosing class templates are not explicitly specialized as well.

like image 147
user657267 Avatar answered Feb 07 '26 10:02

user657267



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