I have this graph structure representing data flow in Prolog.
The function definition_clear_path should compute the definition-clear path of any variable.
When I run this I get the following error:
definition_clear_path/3: Undefined procedure: definition_clear_path1/4
However, there are definitions for:
definition_clear_path/3
When I enter the rule for definition_clear_path1 from the terminal I get Syntax error: Operator expected. Why?
edge(1, 2).
edge(1,3).
edge(3,7).
edge(3,4).
edge(4,6).
edge(4,5).
edge(7,x).
def(p,1).
def(e,1).
def(d,1).
def(x,1).
def(c,1).
def(d,4).
def(t,4).
def(c,5).
def(x, 6).
def(c,6).
use(d,3).
use(e,3).
use(d,4).
use(c,4).
use(x,4).
use(t,4).
use(c,5).
use(x,6).
use(c,6).
use(d,6).
use(x,7).
pos_path(X,Y, [X,Y]):- edge(X,Y).
pos_path(Start, End, [Start|T]) :- edge(Start,Mid), pos_path(Mid, End, T).
definition_clear_path( Node , J , Var ):- definition_clear_path1( Node , J , Var , [ Node ] ) .
definition_clear_path1(B , J, K , F):- edge (B , J ).
definition_clear_path1( Node , J , Var , L):-
edge ( Node , N1 ) ,
not(def( Var , N1 )) ,
not(use( Var , N1 )) ,
definition_clear_path1( N1 , J , Var , [ Node | L ] ) .
Remove the space between edge and the opening parenthesis. Spaces delimit terms, so Prolog will think that edge is an operator rather than the functor of a compound term.
Because of the problems of negation-as-failure, negation in Prolog is represented in modern Prolog interpreters using the symbol \+ , which is supposed to be a mnemonic for not provable with the \ standing for not and the + for provable.
Remove the space between edge and the opening parenthesis.
Spaces delimit terms, so Prolog will think that edge is an operator rather than the functor of a compound term.
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