Starting pthreads simultaneously

Question

What are the different ways of ensuring that a bunch of pthreads all start at the same time?

I could find only one way, ie. initializing a barrier in the main thread, then waiting on it in the newly created pthreads.

Answer 1

That's pretty much exactly how I've done it in the past.

main:
    claim mutex
    for each desired thread:
        start child
    release mutex
    :

child:
    claim mutex
    release mutex
    :

Note that this doesn't actually guarantee that all the threads have started before the first one starts doing something, just that the main thread has created them.

In order to do that, you can use something like the following method:

main:
    claim mutex
    set unstarted to 0
    for each desired thread:
        start child
        add 1 to unstarted
    release mutex
    :

child:
    claim mutex
    subtract 1 from unstarted
    while unstarted > 0:
        release mutex
        yield // if necessary
        claim mutex
    release mutex
    :

Whatever initialisation a thread has to do to be considered started will occur between the claim and the subtract.

---

I see from further investigation that barriers are actually a more elegant way to do this. They weren't actually available in the pthread implementations I used which is why my code may seem a little verbose.

However, I'll leave it as-is on the off-chance that someone uses pre-v6 pthreads or a different threading method (without barriers) and because, as the question asked, this is a different way of doing it.