I have a spring application and I have a native query with this syntax:
select
COUNT(DISTINCT person.id,(CASE WHEN salary_person.rating = 'Satisfactory' THEN 1 END)) AS totalSatisfactory,
COUNT(DISTINCT person.id,(CASE WHEN salary_person.rating = 'Unsatisfactory' THEN 1 END)) AS totalUnsatisfactory
from person
join salary_person on person.id = salary_person.person_id;
I get the error:
ERROR: function count(character varying, integer) does not exist
As database I use PostgreSQL. I mention that in mysql, the query is working.
Postgres does not support count()with more than one column. You can however simply turn both columns into a single column of an anonymous record type, by using something like: (col_one, col_two) - that is a single column of an an anonymous record type.
select COUNT(DISTINCT (person.id,(CASE WHEN salary_person.rating = 'Satisfactory' THEN 1 END))) AS totalSatisfactory,
COUNT(DISTINCT (person.id,(CASE WHEN salary_person.rating = 'Unsatisfactory' THEN 1 END))) AS totalUnsatisfactory
from person
join salary_person on person.id = salary_person.person_id;
Note the parentheses around the two columns.
However, in Postgres you have a more elegant way to do what you want, by using conditional aggregation with the filter clause:
select COUNT(DISTINCT person.id) filter (where salary_person.rating = 'Satisfactory') AS totalSatisfactory,
COUNT(DISTINCT person.id) filter (where salary_person.rating = 'Unsatisfactory') AS totalUnsatisfactory
from person
join salary_person on person.id = salary_person.person_id;
A quick and dirty alternative to count distinct on multiple columns regardless of type is to just concat the two columns into a single column and count distinct that
SELECT
COUNT(DISTINCT CONCAT(person.id, salary_person.rating))
FROM person
JOIN salary_person on person.id = salary_person.person_id;
However, based on what you want to do, can't you just count distinct by rating and filter for certain ratings?
SELECT
salary_person.rating,
COUNT(DISTINCT person.id)
FROM person
JOIN salary_person on person.id = salary_person.person_id
WHERE
salary_person.rating in ('Satisfactory', 'Unsatisfactory')
GROUP BY 1;
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