Solve the random number logic

Question

I have a function called myrand() which generates random number from 1 to 5. I want to make another function by using myrand() that will generate random number form 1 to 7. I write something like that.

function newrand() {
    return myrand()+2;
}

Above logic is not that I want it will never return me 1 or 2. I don't want to use any if condition so what should I do to make logic for random number.

Answer 1

You have a function named rand() in PHP to do this. Try below code:

function newrand() {
    return rand(1, 7);
}

Or lets say your myrand() is something like this below code:

function myrand() {  return rand(1,5); }

What you can do is, pass the upperlimit to myrand() something like myrand(5) and myrand(7) instead of myrand() + 2. Eg below:

myrand($max) {
     return rand(1, $max);
}

and call it like this:

function newrand() {
    return myrand(7);
}