Simpler way to max() two Ordered objects

Question

Given two Ordered vals, I can find maximum using following code:

abstract class C extends Ordered[C] ()

val v1: C = ???
val v2: C = ???

val max = implicitly[Ordering[C]].max(v1, v2)

Can it be done simpler?

Answer 1

If you import Ordering._, you get v1 max v2 (or v1.max(v2), as you might prefer). Also v1 < v2, etc