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The sed command works as expected at the command prompt, but does not work in a shell script.
new_db_name=`echo "$new_db_name" | sed 's/$replace_string/$replace_with/'` Why is that, and how can I fix it?
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The shell is responsible for expanding variables. When you use single quotes for strings, its contents will be treated literally, so sed now tries to replace every occurrence of the literal $var1 by ZZ .
How SED Works. In the syntax, you only need to provide a suitable “new string” name that you want to be placed with the “old string”. Of course, the old string name needs to be entered as well. Then, provide the file name in the place of “file_name” from where the old string will be found and replaced.
A variable is a character string to which we assign a value. The value assigned could be a number, text, filename, device, or any other type of data. A variable is nothing more than a pointer to the actual data. The shell enables you to create, assign, and delete variables.
Use double quotes for the sed expression.
new_db_name=$(echo "$new_db_name" | sed "s/$replace_string/$replace_with/") If you use bash, this should work:
new_db_name=${new_db_name/$replace_string/$replace_with} If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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