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Setting a watch expression in Firebug: ReferenceError - s is not defined

I'm trying to understand how to use firebug to debug my Javascript. So I have the HTML listed below. And I want to set a watch expression on the var 's'. I went to the Script tab of Firebug and opened the Watch pane and entered s into the area that says "New watch expression".

I get an error:

ReferenceError: s is not defined

Why?

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">

<head>

<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>

<style type="text/css">
.StateOne .InitiallyHidden { display: none; }
.StateTwo .InitiallyVisible { display: none; }
</style>

<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.2.6/jquery.min.js"></script>
<script language="javascript" type="text/javascript">
    $(document).ready(function()
    {

        $('.x').click(function() {
               var s = $("#StateContainer")[0];
               s.className = (s.className == 'StateOne' ? 'StateTwo' : 'StateOne');
        });

    });
</script>





</head>

<body>

<button class="x">Change StateContainer</button>

<div class="StateOne" id="StateContainer">
   <div class="InitiallyVisible">Visible first</div>
   <div class="InitiallyHidden">Visible second</div>
   <div class="InitiallyVisible">Visible first</div>
   <div class="InitiallyHidden">Visible second</div>
   <div class="InitiallyVisible">Visible first</div>
   <div class="InitiallyHidden">Visible second</div>
   <div class="InitiallyVisible">Visible first</div>
   <div class="InitiallyHidden">Visible second</div>
</div>



</body>
</html>
like image 872
Charlie Kotter Avatar asked Aug 02 '26 00:08

Charlie Kotter


1 Answers

The variable 's' is only defined inside the click handler for 'x' because it is declared within the function. If you set a breakpoint inside your click function then 's' will work.

It's generally not good practice to create global variables, but for the sake of debugging you could make 's' a global variable by declaring it outside of the $(document).ready() function, like so:

<script language="javascript" type="text/javascript">
    var s;
    $(document).ready(function()
    {

        $('.x').click(function() {
               s = $("#StateContainer")[0];
               s.className = (s.className == 'StateOne' ? 'StateTwo' : 'StateOne');
        });

    });
</script>
like image 187
AgileJon Avatar answered Aug 03 '26 14:08

AgileJon



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