The following command works in CMD (How to start powershell with a window title?).
start powershell -NoExit -command "$Host.UI.RawUI.WindowTitle = 'bits'"
But it doesn't work in Powershell.
PS C:\> start powershell -noexit -command "$Host.UI.RawUI.WindowTitle = 'test'; read-host"
Start-Process : A parameter cannot be found that matches parameter name 'noexit'.
At line:1 char:18
+ start powershell -noexit -command "$Host.UI.RawUI.WindowTitle = 'test ...
+ ~~~~~~~
+ CategoryInfo : InvalidArgument: (:) [Start-Process], ParameterBindingException
+ FullyQualifiedErrorId : NamedParameterNotFound,Microsoft.PowerShell.Commands.StartProcessCommand
The following command can open a new powershell window.
start powershell "$Host.UI.RawUI.WindowTitle = 'test'; read-host"
However, the new window shows the following error message and the title is not set.
System.Management.Automation.Internal.Host.InternalHost.UI.RawUI.WindowTitle : The term
'System.Management.Automation.Internal.Host.InternalHost.UI.RawUI.WindowTitle' is not recognized as the name of a
cmdlet, function, script file, or operable program. Check the spelling of the name, or if a path was included, verify
that the path is correct and try again.
At line:1 char:1
+ System.Management.Automation.Internal.Host.InternalHost.UI.RawUI.Wind ...
+ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
+ CategoryInfo : ObjectNotFound: (System.Manageme...wUI.WindowTitle:String) [], CommandNotFoundException
+ FullyQualifiedErrorId : CommandNotFoundException
Bacon Bits' helpful answer explains that start in cmd.exe means something different than in PowerShell.
Use Start-Process as follows to get the desired result; note that powershell implicitly binds to parameter -FilePath, whereas the ,-separated arguments starting with -NoExit bind implicitly to the -ArgumentList (-Args) parameter, which accepts an array of strings:
# In PowerShell, `start` is an alias for `Start-Process`
start powershell '-NoExit', '-command', "`$Host.UI.RawUI.WindowTitle = 'bits'"
In paticular, --prefixed pass-through arguments must be quoted so that they're not mistaken for Start-Process's own parameters.
Also note the ` preceding the $ in $Host, which prevents up-front interpolation of $Host by the calling PowerShell instance.
You could also use '$Host.UI.RawUI.WindowTitle = ''bits''', a single-quoted literal string with embedded single quotes escaped as ''.
Important:
While passing arguments as an array to -ArgumentList is conceptually the best approach, it is unfortunately ill-advised due to a long-standing bug in Start-Process, still present as of this writing (v7.1) - see GitHub issue #5576.
For now, using a single string comprising all arguments, enclosed in embedded "..." quoting as necessary, is the only generally robust approach. As discussed in the linked GitHub issue, an -ArgumentArray parameter that supports robust array-based argument passing may be introduced in the future.
In the case at hand this means the following, as suggested by PetSerAl in a comment on the question:
Start-Process powershell '-NoExit -command "$Host.UI.RawUI.WindowTitle = ''bits''"'
'...') of the overall argument-list string, which then necessitates escaping the embedded single quotes - those that PowerShell should see as part of the command - as ''.In Command Prompt, start is the start internal command. In Windows Powershell, start is an alias for Start-Process, which does something similar but isn't identical.
Try running this:
powershell -NoExit -command "`$Host.UI.RawUI.WindowTitle = 'bits'"
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