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I'm a newbie to shell scripting and any help is much appreciated.
I have a pattern like this rmd_ver=1.0.10
I want to search the pattern rmd_ver= and replace the numeric part 1.0.10 with a new value in all the matches. Hope my question is clear.
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Find and replace text within a file using sed command Use Stream EDitor (sed) as follows: sed -i 's/old-text/new-text/g' input. txt.
`sed` command is one of the ways to do replacement task. This command can be used to replace text in a string or a file by using a different pattern.
\b marks a word boundary, either beginning or end. Now consider \b' . This matches a word boundary followed by a ' . Since ' is not a word character, this means that the end of word must precede the ' to match.
To replace any value till the end of the line:
sed -i 's/\(rmd_ver=\)\(.*\)/\1R/' file
sed -i 's/p/r/' file replace p with r in file
\( start first grouprmd_ver= search pattern\) end first group\( start second group.* any characters\) end second group\1 back reference to the first groupR replacement textTo replace the exact pattern in any place of the line and possibly several times in one line:
sed -i 's/\(rmd_ver=\)\(1\.0\.10\)/\1R/g' file
\. escape special . into literal .
g to replace multiple occurrences in one line
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