Defining a concat function as below with foldRight can concat list correctly
def concat[T](xs: List[T], ys: List[T]): List[T] = (xs foldRight(ys))(_ :: _)
but doing so with foldLeft
def concat1[T](xs: List[T], ys: List[T]): List[T] = (xs foldLeft(ys))(_ :: _)
results in an compilation error value :: is not a member of type parameter T, need help in understanding this difference.
EDIT :
Just in case someone might be looking for a detailed explanation on folds http://lampwww.epfl.ch/teaching/programmation_avancee/documents/programmation_avancee_5_en-2x2.pdf
Arguments order in foldLeft is not the same as in foldRight.
xs.foldRight(ys){(element, aggregator) => element :: aggregator}
xs.foldLeft(ys){(aggregator, element) => element :: aggregator}
With placeholder syntax for foldLeft - (_ :: _) - you are trying to do something like this: aggregator :: element. This means element.::(aggregator) and there is no :: method in element (type of element is T).
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